Slight wording adjustments.

This commit is contained in:
Bokuan Li
2026-05-31 15:53:32 -04:00
parent 47145cdf58
commit fb8178b7ee

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@@ -153,12 +153,12 @@
\abs{\int_{\gamma_j}\frac{f(z)}{z - z_0}dz - R_j(z)} < \frac{\eps}{n}
\]
so
Thus
\[
\abs{f(z_0) - \sum_{j = 1}^n R_j(z)} < \eps
\]
for all $z_0 \in K$. By the \hyperref[pole pushing lemma]{lemma:pole-pushing}, there exists $S \in \complex(z) \cap H(\complex_\infty \setminus P)$ such that $|S(z_0) - \sum_{j = 1}^n R_j(z_0)| < \eps$ for all $z_0 \in K$.
for all $z_0 \in K$. By the \hyperref[pole pushing lemma]{lemma:pole-pushing}, there exists $S \in \complex(z) \cap H(\complex_\infty \setminus P; \complex)$ such that $|S(z_0) - \sum_{j = 1}^n R_j(z_0)| < \eps$ for all $z_0 \in K$. Therefore $|S(z_0) - f(z_0)| < 2\eps$ for all $z_0 \in K$.
\end{proof}
\begin{corollary}