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Swapped in vocabulary.
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Bokuan Li
2026-06-30 14:14:44 -04:00
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src/measure/vector/fin.tex
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@@ -66,7 +66,7 @@ In any case, the above example shows that a linear functional on $M(X, \cm; \com
In other words, In other words,
\begin{enumerate}[start=2] \begin{enumerate}[start=2]
\item There exists a semifinite measure space $(\Omega, \cn, \mu)$ such that $\mathscr{M} \iso L^1(\Omega; H)$ and $\mathscr{M}^* \iso L^\infty(\Omega; H)$. \item There exists a decomposable measure space $(\Omega, \cn, \mu)$ such that $\mathscr{M} \iso L^1(\Omega; H)$ and $\mathscr{M}^* \iso L^\infty(\Omega; H)$.
\end{enumerate} \end{enumerate}
\end{theorem} \end{theorem}
\begin{proof}[Proof, {{\cite{StackRadonDual}}}. ] \begin{proof}[Proof, {{\cite{StackRadonDual}}}. ]