From e19a5e3ad090be059683d7de03a112d6d7ce757b Mon Sep 17 00:00:00 2001 From: Bokuan Li Date: Tue, 30 Jun 2026 14:14:44 -0400 Subject: [PATCH] Swapped in vocabulary. --- src/measure/vector/fin.tex | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/src/measure/vector/fin.tex b/src/measure/vector/fin.tex index 799abcb..2dcfb68 100644 --- a/src/measure/vector/fin.tex +++ b/src/measure/vector/fin.tex @@ -66,7 +66,7 @@ In any case, the above example shows that a linear functional on $M(X, \cm; \com In other words, \begin{enumerate}[start=2] - \item There exists a semifinite measure space $(\Omega, \cn, \mu)$ such that $\mathscr{M} \iso L^1(\Omega; H)$ and $\mathscr{M}^* \iso L^\infty(\Omega; H)$. + \item There exists a decomposable measure space $(\Omega, \cn, \mu)$ such that $\mathscr{M} \iso L^1(\Omega; H)$ and $\mathscr{M}^* \iso L^\infty(\Omega; H)$. \end{enumerate} \end{theorem} \begin{proof}[Proof, {{\cite{StackRadonDual}}}. ]