Fixed more mistakes in the dyadic rational numbers.
All checks were successful
Compile Project / Compile (push) Successful in 21s
All checks were successful
Compile Project / Compile (push) Successful in 21s
This commit is contained in:
@@ -44,10 +44,10 @@
|
||||
\item[(b)] For each $x, y \in G$, $x + y \ge x, y$.
|
||||
\end{enumerate}
|
||||
|
||||
For each $x \in \mathbb{D} \cap [0, 1)$, let $\phi(x) = \sum_{n \in M(x)}g_n$, then
|
||||
For each $x \in \mathbb{D} \cap (0, 1)$, let $\phi(x) = \sum_{n \in M(x)}g_n$, then
|
||||
\begin{enumerate}
|
||||
\item For any $x, y \in \mathbb{D} \cap [0, 1)$ such that $x + y \in [0, 1)$, $\phi(x) + \phi(y) \le \phi(x + y)$.
|
||||
\item For any $x, y \in \mathbb{D} \cap [0, 1)$ with $x \le y$, $\phi(x) \le \phi(y)$.
|
||||
\item For any $x, y \in \mathbb{D} \cap (0, 1)$ such that $x + y \in (0, 1)$, $\phi(x) + \phi(y) \le \phi(x + y)$.
|
||||
\item For any $x, y \in \mathbb{D} \cap (0, 1)$ with $x \le y$, $\phi(x) \le \phi(y)$.
|
||||
\end{enumerate}
|
||||
\end{proposition}
|
||||
\begin{proof}
|
||||
|
||||
@@ -68,3 +68,10 @@
|
||||
|
||||
Therefore there exists pairs $\bracs{(x_k, y_k)|1 \le k \le N}$ such that $\norm{f(x_k) - f(y_k)}_E \ge 1/n$ for all $n$, and the smallest interval containing each $(x_k, y_k)$ are pairwise disjoint. Thus $[f]_{\text{var}} \ge N/n$ for all $N \in \nat^+$, so $[f]_{\text{var}} = \infty$.
|
||||
\end{proof}
|
||||
|
||||
\begin{proposition}
|
||||
\label{proposition:bounded-variation-one-side-limit}
|
||||
|
||||
\end{proposition}
|
||||
|
||||
|
||||
|
||||
Reference in New Issue
Block a user