Added MCT for convergence in measure.

src/measure/measurable-maps/in-measure.tex

@@ -87,7 +87,7 @@
     (3): By (2), there exists a subsequence $\seq{n_k}$ such that $f_{n_k} \to f$ and $f_{n_k} \to g$ almost everywhere, so $f = g$ almost everywhere. 
 \end{proof}
 
-\begin{theorem}[Monotone Convergence Theorem (In Measure)]
+\begin{theorem}[Monotone Convergence Theorem (in Measure)]
 \label{theorem:mct-measure}
     Let $(X, \cm, \mu)$ be a semifinite measure space, $\net{f} \subset \mathcal{L}^+(X, \cm)$, and $f \in \mathcal{L}^+(X, \cm)$ such that
     \begin{enumerate}[label=(\alph*)]
@@ -117,4 +117,5 @@
     \end{align*}
 
     As the above holds for all $\eps > 0$, $\lambda \in (0, 1)$, $\sup_{\alpha \in A}\int f_\alpha d\mu \ge \int \phi d\mu$. Therefore $\sup_{\alpha \in A}\int f_\alpha d\mu \ge \int f d\mu$ by \autoref{lemma:lebesgue-non-negative-strict}. 
-\end{proof}
+\end{proof}
+