jerrylicious/garden
1
0
Fork 0
Code Issues Pull Requests Actions Packages Projects Releases Wiki Activity

Oxford? comma.

Browse Source
This commit is contained in:
Bokuan Li
2026-06-14 21:26:17 -04:00
parent b8df875d0f
commit 16baef24e7
1 changed files with 1 additions and 1 deletions
Download Patch File Download Diff File Expand all files Collapse all files

2
src/measure/vector/rn.tex
View File

@@ -3,7 +3,7 @@
\begin{theorem}[Lebesgue-Radon-Nikodym] \begin{theorem}[Lebesgue-Radon-Nikodym]
\label{theorem:lebesgue-radon-nikodym} \label{theorem:lebesgue-radon-nikodym}
Let $(X, \cm)$ be a measurable space, $\mu$ be a $\sigma$-finite positive measure on $(X, \cm)$, $H$ be a Hilbert space over $K \in \RC$ and $\nu: \cm \to H$ be a finite vector measure, then there exists a unique pair of finite vector measures $\nu_a, \nu_s: \cm \to H$ such that: Let $(X, \cm)$ be a measurable space, $\mu$ be a $\sigma$-finite positive measure on $(X, \cm)$, $H$ be a Hilbert space over $K \in \RC$, and $\nu: \cm \to H$ be a finite vector measure, then there exists a unique pair of finite vector measures $\nu_a, \nu_s: \cm \to H$ such that:
\begin{enumerate} \begin{enumerate}
\item $\nu = \nu_a + \nu_s$. \item $\nu = \nu_a + \nu_s$.
\item $\nu_a$ is absolutely continuous with respect to $\mu$. \item $\nu_a$ is absolutely continuous with respect to $\mu$.