From 16baef24e7d107b12097af0ed415082b37106c83 Mon Sep 17 00:00:00 2001
From: Bokuan Li <bokuan.li@mail.mcgill.ca>
Date: Sun, 14 Jun 2026 21:26:17 -0400
Subject: [PATCH] Oxford? comma.

---
 src/measure/vector/rn.tex | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/src/measure/vector/rn.tex b/src/measure/vector/rn.tex
index d274633..6473e27 100644
--- a/src/measure/vector/rn.tex
+++ b/src/measure/vector/rn.tex
@@ -3,7 +3,7 @@
 
 \begin{theorem}[Lebesgue-Radon-Nikodym]
 \label{theorem:lebesgue-radon-nikodym}
-    Let $(X, \cm)$ be a measurable space, $\mu$ be a $\sigma$-finite positive measure on $(X, \cm)$, $H$ be a Hilbert space over $K \in \RC$ and $\nu: \cm \to H$ be a finite vector measure, then there exists a unique pair of finite vector measures $\nu_a, \nu_s: \cm \to H$ such that:
+    Let $(X, \cm)$ be a measurable space, $\mu$ be a $\sigma$-finite positive measure on $(X, \cm)$, $H$ be a Hilbert space over $K \in \RC$, and $\nu: \cm \to H$ be a finite vector measure, then there exists a unique pair of finite vector measures $\nu_a, \nu_s: \cm \to H$ such that:
     \begin{enumerate}
         \item $\nu = \nu_a + \nu_s$. 
         \item $\nu_a$ is absolutely continuous with respect to $\mu$.