Updated formulation in BV.
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Bokuan Li
2026-05-01 16:40:01 -04:00
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@@ -65,12 +65,7 @@
\begin{enumerate} \begin{enumerate}
\item $BV([a, b]; E)$ is a vector space. \item $BV([a, b]; E)$ is a vector space.
\item For each continuous seminorm $\rho$ on $E$, $[\cdot]_{\text{var}, \rho}$ is a seminorm on $BV([a, b]; E)$. \item For each continuous seminorm $\rho$ on $E$, $[\cdot]_{\text{var}, \rho}$ is a seminorm on $BV([a, b]; E)$.
\item Let $\fF$ be a filter on $BV([a, b]; E)$ and $f: [a, b] \to E$. If \item For each continuous seminorm $\rho$ on $E$ and $M > 0$, $\bracs{[\cdot]_{\text{var}, \rho} \le M} \subset E^{[a, b]}$ is closed.
\begin{enumerate}[label=\alph*]
\item $\pi_x(\fF) \to f(x)$ for all $x \in [a, b]$.
\item For every continuous seminorm $\rho$ on $E$, there exists $U \in \fF$ such that $\sup_{g \in U}[g]_{\text{var}, \rho} = M_\rho < \infty$.
\end{enumerate}
then $f \in BV([a, b]; E)$ with $[f]_{\text{var}, \rho} \le M_\rho$.
\item For any $f \in BV([a, b]; E)$ and continuous seminorm $\rho$ on $E$, $\sup_{x \in [a, b]}\rho(f(x)) \le \rho(f(a)) + [f]_{\text{var}, \rho}$. \item For any $f \in BV([a, b]; E)$ and continuous seminorm $\rho$ on $E$, $\sup_{x \in [a, b]}\rho(f(x)) \le \rho(f(a)) + [f]_{\text{var}, \rho}$.
\end{enumerate} \end{enumerate}
If $(E, \norm{\cdot}_E)$ is a normed vector space, then If $(E, \norm{\cdot}_E)$ is a normed vector space, then
@@ -79,14 +74,15 @@
\end{enumerate} \end{enumerate}
\end{definition} \end{definition}
\begin{proof}[Proof {{\cite[Proposition X.1.1]{Lang}}}. ] \begin{proof}[Proof {{\cite[Proposition X.1.1]{Lang}}}. ]
(3): Let $\rho$ be a continuous seminorm on $E$ and $P \in \scp([a, b])$, then by assumption (a), (3): Let $\rho$ be a continuous seminorm on $E$, $P = \seqf{x_j} \in \scp([a, b])$, and $f \in \overline{\bracs{[\cdot]_{\text{var}, \rho} \le M}}$. For any $\eps > 0$, there exists $g \in \bracs{[\cdot]_{\text{var}, \rho} \le M}$ such that $\rho(f(x_j) - g(x_j)) < \eps$ for each $1 \le j \le n$. In which case,
\[ \begin{align*}
V_{\rho, P}(f) = \sum_{j = 1}^n \rho(f(x_j) - f(x_{j - 1})) V_{\rho, P}(f) &= \sum_{j = 1}^n \rho(f(x_j) - f(x_{j - 1})) \\
= \lim_{g, \fF}\sum_{j = 1}^n \rho(g(x_j) - g(x_{j - 1})) &\le 2n\eps + \sum_{j = 1}^n \rho(g(x_j) - g(x_{j - 1})) \\
= \lim_{g \in \fF}V_{\rho, P}(g) &\le V_{\rho, P}(g) + 2n\eps \le M + 2n\eps
\] \end{align*}
By assumption (b), $[0, M_\rho]$ is in the filter generated by $V_{\rho, P}(\fF)$. Thus $V_{\rho, P}(f) \le M_\rho$. As this holds for all $P \in \scp([a, b])$, $V_{\rho, P}(f) \le M_\rho$, and $f \in BV([a, b]; E)$.
As the above holds for all $\eps > 0$, $V_{\rho, P}(f) \le M$. Since this holds for all $P \in \scp([a, b])$, $[f]_{\text{var}, \rho} \le M$.
(5): For each $n \in \nat^+$, let (5): For each $n \in \nat^+$, let
\[ \[