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garden/src/dyn/top/recurrence.tex
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\section{Topological Recurrence}
\label{section:tds-recurrence}
\begin{definition}[Periodic]
\label{definition:tds-periodic}
Let $G \curvearrowright X$ be a $G$-flow and $x \in X$, then $x$ is \textbf{periodic} with respect to $G$ if $Gx$ is finite.
\end{definition}
\begin{definition}[Return Set]
\label{definition:tds-return-set}
Let $G \curvearrowright X$ be a $G$-flow, $x \in X$, and $\emptyset \ne U \subset X$, then the \textbf{return set} of $x$ to $U$ is
\[
N(x, U) = \bracsn{g \in G|gx \in U}
\]
\end{definition}
\begin{definition}[Recurrence]
\label{definition:tds-recurrence}
Let $G$ be an infinite group, $G \curvearrowright X$ be a $G$-flow, and $x \in X$, then $x$ is \textbf{recurrent} if for every $U \in \cn_X(x)$, $N(x, U)$ is infinite.
\end{definition}
\begin{definition}[Syndetic]
\label{definition:group-syndetic}
Let $G$ be a group and $S \subset G$, then $S$ is \textbf{(left) syndetic} if there exists $F \subset G$ finite $FS = G$.
\end{definition}
\begin{lemma}
\label{lemma:subgroup-syndetic}
Let $G$ be a group and $H \subset G$ be a subgroup, then $H$ is syndetic if and only if the index of $H$ in $G$ is finite.
\end{lemma}
% Proof omitted.
\begin{definition}[Uniformly Recurrent]
\label{definition:tds-uniformly-recurrent}
Let $G \curvearrowright X$ be a $G$-flow and $x \in X$, then $x$ is \textbf{uniformly recurrent} if for every $U \in \cn_X(x)$, $N(x, U)$ is syndetic.
\end{definition}