RETRACTION: wrong word used.
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Bokuan Li
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@@ -38,12 +38,13 @@
\begin{proposition}
\label{proposition:positive-automatic-continuity}
Let $A, B$ be $C^*$-algebra, $S \subset A$ and $T \subset B$ be operator systems, and $\phi: S \to T$ be a positive map, then
\[
\norm{\phi}_{L(S; T)} \le 2\norm{\phi(1_A)}_B
\]
\begin{enumerate}
\item For any $x \in S_{sa}$, $\norm{\phi(x)}_{B} \le \norm{\phi(1_A)}_B \cdot \norom{x}_A$.
\item $\norm{\phi}_{L(S; T)} \le 2\norm{\phi(1_A)}_B$.
\end{enumerate}
\end{proposition}
\begin{proof}
Let $x \in T_+$, then $0 \le x \le \norm{x}_A$, and $0 \le \phi(x) \le \norm{x}_A \cdot \norm{\phi(1_A)}_B$, so $\norm{\phi(x)}_B \le \norm{x}_A \cdot \norm{\phi(1_A)}_B$.
(1): Let $x \in T_+$, then $0 \le x \le \norm{x}_A$, and $0 \le \phi(x) \le \norm{x}_A \cdot \norm{\phi(1_A)}_B$, so $\norm{\phi(x)}_B \le \norm{x}_A \cdot \norm{\phi(1_A)}_B$.
For any $x, y \in T_+$, $x - y \le x$ and $y - x \le y$. As such,
\[
@@ -57,7 +58,7 @@
&\le \norm{s}_A \norm{\phi(1_A)}_B
\end{align*}
Finally, for any general $s \in S$,
(2): For any general $s \in S$,
\begin{align*}
\phi(s) &= \phi(\text{Re}(s)) + i\phi(\text{Im}(s)) \\
\norm{\phi(s)}_B &\le \norm{\phi(\text{Re}(s))}_B + \norm{\phi(\text{Im}(s))}_{B} \\
@@ -65,6 +66,35 @@
\end{align*}
\end{proof}
\begin{theorem}
\label{theorem:positive-commutative-norm}
Let $X$ be a compact Hausdorff space, $A$ be a unital $C^*$-algebra and $\phi: C(X; \complex) \to A$ be a positive map, then $\norm{\phi}_{L(C(X; \complex); B)} = \norm{\phi(\one)}_{B}$.
\end{theorem}
\begin{proof}
Assume without loss of generality that $\norm{\phi(\one)}_{B} \le 1$.
Let $\seqf{h_j} \subset C(X; [0, 1])$ be a partition of unity on $X$, and $\seqf{\lambda_j} \subset \ol{B_\complex(0, 1)}$.
Since $A$ is a unital $C^*$-algebra, there exists a complex Hilbert space $H$ such that $A$ may be identified with a $C^*$-subalgebra of $B(H)$, with $1_A = 1_{B(H)}$. In which case, for any $\xi, \eta \in H$,
\begin{align*}
\abs{\sum_{j = 1}^n \dpn{\lambda_j \phi(h_j)\xi, \eta}{H}} &\le \sum_{j = 1}^n \abs{\dpn{\phi(h_j)\xi, \eta}{H}} \\
&= \sum_{j = 1}^n\abs{\dpn{\phi(h_j)^{1/2}\xi, \phi(h_j)^{1/2}\eta}{H}} \\
&\le \braks{\sum_{j = 1}^n \normn{\phi(h_j)^{1/2}\xi}_H^2}^{1/2} \cdot \braks{\sum_{j = 1}^n\normn{\phi(h_j)^{1/2}\eta}_H^2}^{1/2}\\
&\le \braks{\sum_{j = 1}^n \dpn{\phi(h_j)\xi, \xi}{H}}^{1/2} \cdot \braks{\sum_{j = 1}^n\dpn{\phi(h_j)\xi, \xi}{H}}^{1/2} \\
&\le \braks{\angles{\sum_{j = 1}^n \phi(h_j)\xi, \xi}{H}}^{1/2} \cdot \braks{\angles{\sum_{j = 1}^n \phi(h_j)\eta, \eta}{H}}^{1/2} \\
&\le (\dpn{\xi, \xi}{H})^{1/2}(\dpn{\eta, \eta}{H})^{1/2} = \norm{\xi}_H \norm{\eta}_H
\end{align*}
so $\normn{\sum_{j = 1}^n \lambda_j\phi(h_j)}_A \le 1$.
Let $f \in C(X; \complex)$ with $\norm{f}_u \le 1$ and $\eps > 0$, then there exists a partition of unity $\seqf{h_j} \subset C(X; [0, 1])$ such that for each $1 \le j \le n$, $\sup_{x, y \in \supp{h_j}}|f(x) - f(y)| < \eps$. For each $1 \le j \le n$, choose $x_j \in \supp{h_j}$, then $\norm{f - \sum_{j = 1}^n f(x_j)h_j}_u \le \eps$.
By the previous case and \autoref{proposition:positive-automatic-continuity},
\[
\norm{\phi(f)}_A \le \norm{\sum_{j = 1}^n f(x_j)\phi(h_j)}_A + 2\norm{f - \sum_{j = 1}^n f(x_j)h_j}_u \le 1 + 2\eps
\]
\end{proof}
\begin{example}[Arveson]
\label{example:positive-automatic-continuity}
@@ -81,7 +111,10 @@
\begin{enumerate}
\item $\phi$ is a positive map.
\item $\norm{\phi}_{L(C(\mathbb{T} ; \complex); M_2(\complex))} = 2$.
\item $\phi$ admits no extension to a positive map on $C(\mathbb{T}; \complex)$.
\end{enumerate}
As such, $M_2(\complex)$ is not injective with respect to operator systems and positive maps.
\end{example}
\begin{proof}[Proof, {{\cite[Example 2.2]{Paulsen}}}. ]
(1): Let $a + bz + c \ol z \in S$, then the following are equivalent:
@@ -95,4 +128,7 @@
(2): $\norm{\phi(z)}_{M_2(\complex)} = 2$.
(3): By \autoref{theorem:positive-commutative-norm}, any such extension would have norm $1$.
\end{proof}