RETRACTION: wrong word used.
Compile Project / Compile (push) Successful in 1m0s

This commit is contained in:
Bokuan Li
2026-09-24 21:31:39 -04:00
parent 864586a997
commit ff7031a4ae
6 changed files with 66 additions and 18 deletions
+2 -2
View File
@@ -59,10 +59,10 @@
\begin{corollary}
\label{corollary:stonean-commutative-algebra}
Let $A$ be a unital $C^*$-algebra, then $A_{sa}$ is order complete if and only if $\Omega(A)$ is extremely disconnected.
Let $A$ be a unital $C^*$-algebra, then $A_{sa}$ is order complete if and only if $\Omega(A)$ is extremally disconnected.
\end{corollary}
\begin{proof}
By \autoref{theorem:gelfand-naimark}, $A$ and $C(\Omega(A); \complex)$ are isomorphic as $C^*$-algebras. In particular, $A_{sa}$ and $C(\Omega(A); \real)$ are isomorphic as ordered vector spaces, so $A_{sa}$ is order complete if and only if $C(\Omega(A); \real)$ is order complete. Thus the \hyperref[Stone-Nakano Theorem]{theorem:stone-nakano-extremely-disconnected} implies that $A_{sa}$ is order complete if and only if $\Omega(A)$ is extremely disconnected.
By \autoref{theorem:gelfand-naimark}, $A$ and $C(\Omega(A); \complex)$ are isomorphic as $C^*$-algebras. In particular, $A_{sa}$ and $C(\Omega(A); \real)$ are isomorphic as ordered vector spaces, so $A_{sa}$ is order complete if and only if $C(\Omega(A); \real)$ is order complete. Thus the \hyperref[Stone-Nakano Theorem]{theorem:stone-nakano-extremally-disconnected} implies that $A_{sa}$ is order complete if and only if $\Omega(A)$ is extremally disconnected.
\end{proof}