diff --git a/src/op/banach/definitions.tex b/src/op/banach/definitions.tex index bc3b4fa..6fc40e4 100644 --- a/src/op/banach/definitions.tex +++ b/src/op/banach/definitions.tex @@ -27,5 +27,44 @@ \end{enumerate} \end{definition} +\begin{definition}[Unital Homomorphism] +\label{definition:banach-algebra-unital-homomorphism} + Let $A, B$ be unital Banach algebras and $\phi: A \to B$ be a homomorphism, then $\phi$ is a \textbf{unital homomorphism} if $\phi(1) = 1$. +\end{definition} + +\begin{definition}[Unitisation] +\label{definition:unitisation} + Let $A$ be a Banach algebra over $\complex$, and $\tilde A = \complex \oplus A$ with + \[ + \iota: A \to \complex \oplus A \quad x \mapsto 0 + x + \] + + For each $\lambda + x, \mu + y \in \tilde A$, define + \[ + (\lambda + x)(\mu + y) = \lambda \mu + (\lambda x + \mu x + xy) + \] + + and + \[ + \norm{\lambda + x}_{\tilde A} = |\lambda| \norm{x}_A + \] + + then + \begin{enumerate} + \item $\tilde A$ is a unital associative algebra over $\complex$. + \item $\iota: A \to \tilde A$ is a homomorphism. + \item[(U)] For any pair $(B, \phi)$ satisfying (1) and (2), there exists a unique continuous unital homomorphism $\tilde \phi: \tilde A \to B$ such that $\phi(1) = 1$ and the following diagram commutes: + \xymatrix{ + \tilde A \ar@{->}[r]^{\tilde \phi } & B \\ + A \ar@{->}[u]^{\iota} \ar@{->}[ru]_{\phi} & + } + \item $\iota(A)$ is a closed two-sided ideal of $\tilde A$. + \end{enumerate} + + The algebra $\tilde A$ is the \textbf{unitisation} of $A$. +\end{definition} +\begin{proof} + (U): For each $\lambda + x \in \tilde A$, let $\tilde \phi(\lambda + x) = \lamdba + \phi(x)$. +\end{proof} diff --git a/src/op/banach/gelfand.tex b/src/op/banach/gelfand.tex index f38d2c5..5345bba 100644 --- a/src/op/banach/gelfand.tex +++ b/src/op/banach/gelfand.tex @@ -19,7 +19,6 @@ \label{proposition:gelfand-transform-gymnastics} Let $A$ be a commutative unital Banach algebra and $x \in A$, then: \begin{enumerate} - \item $\Gamma_A$ is a contractive homomorphism. \item $\Gamma_A(1) = 1$. \item $x \in G(A)$ if and only if $\Gamma_A x \in G(C(\Omega(A); \complex))$. \item $(\Gamma_Ax)(\Omega(A)) = \sigma_A(x)$. diff --git a/src/op/banach/multiplicative.tex b/src/op/banach/multiplicative.tex index 25e94fa..d82de0f 100644 --- a/src/op/banach/multiplicative.tex +++ b/src/op/banach/multiplicative.tex @@ -14,7 +14,6 @@ \item $\norm{\phi}_{A^*} = 1$. \item $\phi(G(A)) \subset \complex \setminus \bracs{0}$. \end{enumerate} - \end{proposition} \begin{proof} (3): For each $x \in G(A)$, $1 = \phi(xx^{-1}) = \phi(x)\phi(x^{-1}) \ne 0$. @@ -24,12 +23,27 @@ (2): For each $\lambda \in \complex$, $\phi(\lambda 1) = \lambda$, so $\norm{\phi}_{A^*} \le 1$. \end{proof} +\begin{proposition} +\label{proposition:multiplicative-less-unit} + Let $A$ be a Banach algebra and $\phi \in A^*$ be a multiplicative functional, then $\norm{\phi}_{A^*} \le 1$. +\end{proposition} +\begin{proof} + Let $\tilde A$ be the unitisation of $A$, then by (U) of the \hyperref[unitisation]{definition:unitisation}, $\phi$ extends to a multiplicative functional $\tilde \phi$ on $\tilde A$. Therefore $\norm{\phi}_{A^*} \le \normn{\tilde \phi}_{{\tilde A}^*} = 1$. +\end{proof} + + \begin{definition}[Space of Multiplicative Linear Functionals] \label{definition:multiplicative-linear-functional-space} - Let $A$ be a unital Banach algebra, then $\Omega(A)$ is the \textbf{space of multiplicative linear functionals}, which is a compact Hausdorff space under the weak-* topology. + Let $A$ be a Banach algebra, then $\Omega(A)$ is the \textbf{space of multiplicative linear functionals}, and with respect to the weak-* topology, + \begin{enumerate} + \item If $A$ is unital, then $\Omega(A)$ is a compact Hausdorff space. + \item $\Omega(A) \cup \bracs{0}$ is a compact Hausdorff space, and $\Omega(A)$ is a LCH space. + \end{enumerate} \end{definition} \begin{proof} - By the \hyperref[Banach-Alaoglu Theorem]{theorem:alaoglu}. + (1): By \autoref{proposition:multiplicative-unit}, $\Omega(A)$ is a weak-* closed subset of $\bracsn{\phi \in A^*:\norm{\phi}_{A^*} = 1}$, so it is compact by the \hyperref[Banach-Alaoglu Theorem]{theorem:alaoglu}. + + (2): By \autoref{proposition:multiplicative-less-unit}, $\Omega(A) \cup \bracs{0}$ is a weak-* closed subset of $\ol{B_{A^*}(0, 1)}$, so it is compact by the \hyperref[Banach-Alaoglu Theorem]{theorem:alaoglu}. \end{proof} \begin{proposition}