Added characterisation of positive linear functionals.
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Bokuan Li
2026-07-07 17:26:52 -04:00
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\input{./homomorphism.tex}
\input{./gelfand.tex}
\input{./cont.tex}
\input{./order.tex}
\input{./order.tex}
\input{./positive.tex}

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\section{Positive Linear Functionals}
\label{section:cstar-positive}
\begin{definition}[Positive Linear Functional]
\label{definition:cstar-positive-functional}
Let $A$ be a unital $C^*$-algebra and $\phi \in A^*$, then $\phi$ is \textbf{positive} if $\dpn{x, \phi}{A} \ge 0$ for all positive elements $x \in A$.
\end{definition}
\begin{theorem}
\label{theorem:cstar-positive-algebraic}
Let $A$ be a unital $C^*$-algebra and $\phi \in \hom(A; \complex)$, then the following are equivalent:
\begin{enumerate}
\item $\phi$ is a positive linear functional.
\item $\phi \in A^*$ with $\normn{\phi}_{A^*} = \dpn{1, \phi}{A}$.
\end{enumerate}
\end{theorem}
\begin{proof}
(1) $\Rightarrow$ (2): For any $x \in A_{sa}$ with $\norm{x}_A \le 1$, $\sigma_A(1 - x) \subset 1 - [-1, 1] = [0, 2]$ by \autoref{proposition:commutative-spectrum-gymnastics}. Thus $1 - x \ge 0$ by \autoref{proposition:positive-spectrum}, and $\dpn{x, \phi}{A} \le \dpn{1, \phi}{A}$. By \autoref{proposition:hermitian-functional-norm}, $\norm{\phi}_{A^*} \le \dpn{1, \phi}{A}$, so $\norm{\phi}_{A^*} = \dpn{1, \phi}{A}$.
(2) $\Rightarrow$ (1): For each $x \in A_{sa}$, by restricting to $A[x]$, assume without loss of generality that $A$ is commutative. By the \autoref{theorem:riesz-radon-c0}, $\phi$ takes the form of a Radon measure $\mu$ on $\Omega(A)$, and $\norm{\phi}_{A^*} = \norm{\mu}_{\text{var}}$. For each Borel set $E \in \cb_{\Omega(A)}$,
\begin{align*}
\norm{\mu}_{\text{var}} &= \int_{\Omega(A)} 1 d\mu = \mu(E) + \mu(\Omega(A) \setminus E) \\
&\le |\mu(E)| + |\mu(\Omega(A) \setminus E)| \le \norm{\mu}_{\text{var}}
\end{align*}
which is only possible if $\mu(E), \mu(\Omega(A) \setminus E) \ge 0$. As this holds for all $E \in \cb_{\Omega(A)}$, $\mu$ is positive, and $\phi$ then is a positive linear functional.
\end{proof}

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Let $A$ be an involutive algebra over $\complex$ and $x \in A$, then $x$ is \textbf{self-adjoint} if $x = x^*$. The space $A_{sa} = \bracs{x \in A| x = x^*}$ is the \textbf{self-adjoint part} of $A$, and:
\begin{enumerate}
\item $A_{sa}$ is a $\real$ subspace of $A$.
\item $A = \complex(A_{sa})$ as a vector space.
\item $A = \complex(A_{sa})$, with equivalent norms.
\item For each $x \in A$, let
\[
\text{Re}(x) = \frac{x + x^*}{2} \quad \text{Im}(x) = \frac{x - x^*}{2i}
@@ -64,7 +64,7 @@
\end{enumerate}
\end{corollary}
\begin{proof}
(1): Since $\sigma_A(x)$ is compact, there exisst $\lambda \in \sigma_A(x)$ such that $|\lambda| = [x]_{sp}$. By \autoref{theorem:c-star-normal-spectral-radius}, $|\lambda| = [x]_{sp} = \norm{x}_A$.
(1): Since $\sigma_A(x)$ is compact, there exists $\lambda \in \sigma_A(x)$ such that $|\lambda| = [x]_{sp}$. By \autoref{theorem:c-star-normal-spectral-radius}, $|\lambda| = [x]_{sp} = \norm{x}_A$.
(2): By the \hyperref[Spectral Mapping Theorem]{theorem:spectral-mapping-holomorphic},
\[