From c81b77a721e4274457ebee2d0fd0ed21f4334bb9 Mon Sep 17 00:00:00 2001 From: Bokuan Li Date: Wed, 24 Jun 2026 22:06:22 -0400 Subject: [PATCH] Added the separable corollary to the Legendre transform. --- src/fa/convex/legendre.tex | 23 +++++++++++++++++++++++ 1 file changed, 23 insertions(+) diff --git a/src/fa/convex/legendre.tex b/src/fa/convex/legendre.tex index 5daaff1..f3b6de0 100644 --- a/src/fa/convex/legendre.tex +++ b/src/fa/convex/legendre.tex @@ -217,5 +217,28 @@ By \autoref{lemma:conjugate-function-gymnatics}, $f^{**}$ is lower semicontinuous and convex with so $f^{**} \le f$, so $\text{epi}(f^{**}) \supset \text{epi}(f)$ and $\text{epi}(f^{**}) \supset \ol{\text{Conv}}(\text{epi}(f))$. \end{proof} +\begin{corollary} +\label{corollary:separable-legendre} + Let $\dpn{E, F}{\lambda}$ be a duality over $\real$, and $f: E \to (-\infty, \infty]$ with $f \ne \infty$ be convex and lower semicontinuous, then there exists $\seq{(\phi_n, \alpha_n)} \subset F \times \real$ such that for each $x \in E$, + \[ + f(x) = \sup_{n \in \natp} \dpn{x, \phi_n}{\lambda} - \alpha_n + \] +\end{corollary} +\begin{proof} + For each $(\phi, \alpha) \in F \times \real$, denote $(\phi, \alpha) \le f$ if $\dpn{\cdot, \phi}{\lambda} - \alpha \le f$. By the \hyperref[Fenchel-Moreau Theorem]{theorem:fenchel-moreau}, + \[ + f^{**}(x) = \sup\bracs{\dpn{x, \phi}{\lambda} - \alpha|(\phi, \alpha) \in F \times \real, (\phi, \alpha) \le f} + \] + + for all $x \in E$. By \autoref{proposition:separable-dual}, + \[ + S = \bracs{(\phi, \alpha) \in F \times \real| (\phi, \alpha) \le f} + \] + + is separable with respect to $\sigma(F \times \real, E \times \real)$. Therefore there exists $\seq{(\phi_n, \alpha_n)} \subset S$ such that for each $x \in E$, + \[ + f(x) = \sup_{n \in \natp} \dpn{x, \phi_n}{\lambda} - \alpha_n + \] +\end{proof}