Fixed awkward phrasing.
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@@ -103,7 +103,7 @@ Despite the fact that it does not cover the full dual space, the bounded Borel f
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\item[(P)] For each $x \in X$, $\bracs{x} \in \cm$, and the delta mass $\delta_x$ is in $\mathscr{M}$.
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\item[(P)] For each $x \in X$, $\bracs{x} \in \cm$, and the delta mass $\delta_x$ is in $\mathscr{M}$.
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\end{enumerate}
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\end{enumerate}
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then for any sequence $f_n: X \to E^*$ of bounded measurable functions and $f: X \to E^*$ be a bounded measurable function, the following are equivalent:
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Then, for any bounded measurable functions $\bracsn{f_n: X \to E^*|n \in \natp}$ and $f: X \to E^*$, the following are equivalent:
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\begin{enumerate}
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\begin{enumerate}
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\item For each $\mu \in \mathscr{M}$, $\limv{n}\int f_n d\mu = \int f d\mu$.
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\item For each $\mu \in \mathscr{M}$, $\limv{n}\int f_n d\mu = \int f d\mu$.
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\item For each $x \in X$, $\limv{n}f_n(x) = f(x)$, and $\sup_{n \in \natp}\norm{f_n}_u < \infty$.
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\item For each $x \in X$, $\limv{n}f_n(x) = f(x)$, and $\sup_{n \in \natp}\norm{f_n}_u < \infty$.
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