Added inductive limits of TVS.

src/fa/tvs/inductive.tex

@@ -0,0 +1,70 @@
+\section{Inductive Limits}
+\label{section:tvs-inductive}
+
+\begin{definition}[Inductive Topology]
+\label{definition:tvs-inductive}
+    Let $\seqi{E}$ be TVSs over $K \in \RC$, $\seqi{T}$ such that $T_i \in \hom(E_i; E)$ for all $i \in I$, and $E$ be a vector space over $K$, then there exists a topology $\topo$ on $E$ such that:
+    \begin{enumerate}
+        \item $(E, \topo)$ is a TVS over $K$.
+        \item For each $i \in I$, $T_i \in L(E_i; E)$.
+        \item[(U)] For any topology $\mathcal{S}$ on $E$ satisfying (1) and (2), $\mathcal{S} \subset T$.
+        \item For any TVS $F$ and $T \in \hom(E; F)$, $T \in L(E; F)$ if and only if $T \circ T_i \in L(E_i; F)$ for all $i \in I$.
+    \end{enumerate}
+    The topology $\topo$ is the \textbf{inductive topology} on $E$ induced by $\seqi{T}$.
+\end{definition}
+\begin{proof}
+    (1): Let
+    \[
+    \mathcal{B} = \bracs{U \subset E|U \text{ radial, circled}, T_i^{-1}(U) \in \cn_{E_i}(0) \forall i \in I}
+    \]
+    To see that $\mathcal{B}$ is a fundamental system of neighbourhoods at $0$ for a vector space topology on $E$, it is sufficient to verify the following and apply \ref{proposition:tvs-0-neighbourhood-base}.
+    \begin{enumerate}
+        \item[(TVB1)] Every set in $\mathcal{B}$ is radial and circled by definition.
+        \item[(TVB2)] For any $U \in \mathcal{B}$, $U$ is circled, so $\frac{1}{2}U + \frac{1}{2}U \subset U$. Since $\frac{1}{2}U$ is also circled and radial, $\frac{1}{2}U \in \mathcal{B}$.
+    \end{enumerate}
+
+    Let $\topo$ be the vector space topology such that $\mathcal{B}$ is a fundamental system of neighbourhoods at $0$, then $(E, \topo)$ is a TVS.
+
+    (2): For each $i \in I$ and $U \in \mathcal{B}$, $T_i^{-1}(U) \in \cn_{E_i}(0)$, so $T_i \in L(E_i; E)$.
+
+    (U): Let $U \in \cn_{(E, \mathcal{S})}(0)$ be circled and radial, then by (2), $T_i^{-1}(U) \in \cn_{E_i}(0)$ for all $i \in I$. Thus the circled and radial neighbourhoods of $0$ in $(E, \mathcal{S})$ is a subset of $\mathcal{B}$.
+
+    (4): Let $U \in \cn_F(0)$ be circled and radial and $i \in I$. Since $T \circ E_i \in L(E_i; F)$, $T_i^{-1}(T^{-1}(U)) \in \cn_{E_i}(0)$, so $T^{-1}(U) \in \mathcal{B} \subset \cn_E(0)$.
+\end{proof}
+
+\begin{definition}[Inductive Limit]
+\label{definition:tvs-inductive-limit}
+    Let $(\seqi{E}, \bracsn{T^i_j| i, j \in I, i \lesssim j})$ be an upward-directed system of TVSs over $K \in \RC$, then there exists $(E, \bracsn{T^i_E}_{i \in I})$ such that:
+    \begin{enumerate}
+        \item $E$ is a TVS over $K$.
+        \item For each $i \in I$, $T^i_E \in L({E_i, E})$.
+        \item For any $i, j \in I$ with $i \lesssim j$, the following diagram commutes:
+
+        \[
+        \xymatrix{
+        E_i \ar@{->}[rd]_{T^i_E} \ar@{->}[r]^{T^i_j} & E_j \ar@{->}[d]^{T^j_E} \\
+        & E
+        }
+        \]
+
+        \item[(U)] For any pair $(F, \bracsn{S^i_F}_{i \in I})$ satisfying (1) and (2), there exists a unique $S \in L({E, F})$ such that the following diagram commutes
+
+        \[
+        \xymatrix{
+        E_i \ar@{->}[d]_{T^i_E} \ar@{->}[rd]^{S^i_F} &  \\
+        E \ar@{->}[r]_{S} & F
+        }
+        \]
+
+        for all $i \in I$.
+        \item For any TVS $F$ and $T \in \hom(E; F)$, $T \in L(E; F)$ if and only if $T \circ T^i_E \in L(E_i; F)$ for all $i \in I$.
+    \end{enumerate}
+    The pair $(E, \bracsn{T^i_E}_{i \in I})$ is the \textbf{inductive limit} of $(\seqi{E}, \bracsn{T^i_j| i, j \in I, i \lesssim j})$.
+\end{definition}
+\begin{proof}
+    Let $(E, \bracsn{T^i_E}_{i \in I})$ be the direct limit of $(\seqi{E}, \bracsn{T^i_j| i, j \in I, i \lesssim j})$ as vector spaces over $K$ (\ref{proposition:module-direct-limit}). Equip $E$ with the inductive topology (\ref{definition:tvs-inductive}) induced by $\bracsn{T^i_E}_{i \in I}$, then $(E, \bracsn{T^i_E}_{i \in I})$ satisfies (1), (2), and (3).
+
+    (U): By (U) of \ref{proposition:module-direct-limit}, there exists a unique $S \in \hom(E; F)$ such that the given diagram commutes. By (4) of \ref{definition:tvs-inductive}, $S \in L(E; F)$.
+
+    (5): By (5) of \ref{definition:tvs-inductive}.
+\end{proof}