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src/topology/functions/index.tex
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src/topology/functions/index.tex
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\chapter{Function Spaces}
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\label{chap:function-spaces}
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\input{./src/topology/functions/set-systems.tex}
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src/topology/functions/set-systems.tex
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src/topology/functions/set-systems.tex
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\section{Topology With Respect to Families of Sets}
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\label{section:pointwise}
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\begin{definition}[Set-Open Topology]
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\label{definition:set-open}
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Let $T$ be a set, $\mathfrak{S} \subset 2^T$ be a non-empty family of sets, and $(X, \topo)$ be a topological space. For each $S \in \mathfrak{S}$ and $U \subset X$ open, let
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\[
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M(S, U) = \bracs{f \in X^T| f(S) \subset U}
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\]
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and
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\[
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\ce(\mathfrak{S}, \topo) = \bracs{M(S, U)| S \in \mathfrak{S}, U \in \topo}
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\]
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then the topology generated by $\ce$ is the \textbf{$\mathfrak{S}$-open topology} on $T^X$.
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If $\cb \subset \topo$ generates $\topo$, then $\ce(\mathfrak{S}, \cb)$ generates the $\mathfrak{S}$-open topology.
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\end{definition}
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\begin{definition}[Set Uniformity]
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\label{definition:set-uniform}
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Let $T$ be a set, $\mathfrak{S} \subset 2^T$ be a non-empty family of sets, and $(X, \fU)$ be a uniform space. For each $S \in \mathfrak{S}$ and $U \in \fU$, let
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\[
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E(S, U) = \bracs{(f, g) \in X^T|(f(x), g(x)) \in U \forall x \in S}
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\]
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and
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\[
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\mathfrak{E}(\mathfrak{S}, \fU) = \bracs{E(S, U)| S \in \mathfrak{S}, U \in \fU}
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\]
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then
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\begin{enumerate}
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\item $\mathfrak{E}(\mathfrak{S}, \fU)$ generates a uniformity $\fV$ on $X^T$.
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\item The topology induced by $\fV$ is finer than the $\mathfrak{S}$-topology on $T^X$.
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\item If $\mathfrak{S}$ is upward-directed with respect to inclusion, then $\mathfrak{E}(\mathfrak{S}, \fU)$ is forms a fundamental system of entourages for $\fV$.
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\end{enumerate}
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and the topology induced by $\fV$ is the \textbf{topology of uniform convergence on the sets $\mathfrak{S}$}, or the $\mathfrak{S}$-topology.
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\end{definition}
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\begin{proof}
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(1): Since $\Delta \subset E(S, U)$ for all $S \in \mathfrak{S}$ and $U \in \fU$, $\mathfrak{E}(\mathfrak{S}, \fU)$ generates a uniformity on $X^T$.
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(2): Let $U \subset X$ be open, then for each $x \in U$, there exists $V_x \in \fU$ such that $x \in V_x(x) \subset U$. In which case, $U = \bigcup_{x \in U}V_x(x)$ and $M(S, U) = \bigcup_{x \in U}M(S, V_x)(x)$.
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(3): It is sufficient to verify
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\begin{enumerate}
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\item[(FB1)] For any $S, S' \in \mathfrak{S}$, there exists $T \in \mathfrak{S}$ with $T \supset S, S'$. In which case, for any $U, U' \in \fU$,
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\[
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E(T, U \cap U') \subset E(S \cup S', U \cap U') \subset E(S, U) \cap E(S', U')
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\]
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\item[(FB3)] For any $U \in \fU$, there exists $V \in \fV$ with $V \circ V \subset U$. Thus for any $S \in \mathfrak{S}$,
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\[
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E(S, V) \circ E(S, V) \subset E(S, V \circ V) \subset E(S, U)
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\]
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\end{enumerate}
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By \ref{proposition:fundamental-entourage-criterion}, $\mathfrak{E}$ is a fundamental system of entourages for the uniformity that it generates.
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\end{proof}
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\part{General Topology}
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\label{part:-part-topology}
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\label{part:topology}
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\input{./src/topology/main/index.tex}
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\input{./src/topology/uniform/index.tex}
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\input{./src/topology/functions/index.tex}
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\label{definition:baire}
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Let $X$ be a topological space, then the following are equivalent:
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\begin{enumerate}
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\item For any $\seq{A_n}$ nowhere dense, $\bigcup_{n \in \nat}A_n \subsetneq X$.
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\item For any $\seq{A_n}$ closed with empty interior, $\bigcup_{n \in \nat}A_n \subsetneq X$.
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\item For any $\seq{A_n}$ closed with $\bigcup_{n \in \nat}A_n = X$, there exists $N \in \nat$ such that $\bigcup_{n \le N}A_n$ has non-empty interior.
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\item For any $\seq{U_n}$ open and dense, $\bigcap_{n \in \nat}U_n$ is dense.
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\item For any $\seq{A_n}$ nowhere dense, $\bigcup_{n \in \nat^+}A_n \subsetneq X$.
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\item For any $\seq{A_n}$ closed with empty interior, $\bigcup_{n \in \nat^+}A_n \subsetneq X$.
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\item For any $\seq{A_n}$ closed with $\bigcup_{n \in \nat^+}A_n = X$, there exists $N \in \nat^+$ such that $\bigcup_{n \le N}A_n$ has non-empty interior.
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\item For any $\seq{U_n}$ open and dense, $\bigcap_{n \in \nat^+}U_n$ is dense.
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\end{enumerate}
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If the above holds, then $X$ is a \textbf{Baire space}.
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\end{definition}
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Conversely, if $\cb \subset 2^X$ is a family such that:
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\begin{enumerate}
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\item[(TB1)] For every $x \in X$, there exists $U \in \cb$ such that $x \in U$.
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\item[(TB2)] For every $x \in X$ and $U, V \in \cb$ such that $x \in U \cap$, there exists $W \in \cb$ such that $x \in W \subset U \cap V$.
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\item[(TB2)] For every $x \in X$ and $U, V \in \cb$ such that $x \in U \cap V$, there exists $W \in \cb$ such that $x \in W \subset U \cap V$.
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\end{enumerate}
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then $\topo(\cb)$ is a topology on $X$, and $\cb$ is a base for $\topo(\cb)$.
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\end{definition}
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\begin{lemma}
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\label{lemma:uniform-first-countable}
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Let $X$ be a uniform space with a countable fundamental system of entourages, then there exists a countable fundamental system of symmetric entourages $\fB = \bracs{U_{1/2^n}|n \in \nat^+}$ such that $U_{1/2^{n+1}} \circ U_{1/2^{n+1}} \subset U_{1/2^n}$ for all $n \in \nat$.
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Let $X$ be a uniform space with a countable fundamental system of entourages, then there exists a countable fundamental system of symmetric entourages $\fB = \bracs{U_{1/2^n}|n \in \nat^+}$ such that $U_{1/2^{n+1}} \circ U_{1/2^{n+1}} \subset U_{1/2^n}$ for all $n \in \nat^+$.
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\end{lemma}
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\begin{proof}
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Let $\seq{V}$ be a countable fundamental system of entourages. By \ref{lemma:symmetricfundamentalentourage}, there exists a symmetric entourage $U_{1/2} \subset V_1$. Suppose inductively that $U_{1/2^n}$ has been constructed, then by (U2) and \ref{lemma:symmetricfundamentalentourage}, there exists a symmetric entourage $U_{1/2^{n+1}} \subset U_{1/2^n} \cap V$. Thus $\fB = \bracs{U_{1/2^n}|n \in \nat^+}$ is the desired family.
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