Finished basic function space topologies.

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Bokuan Li
2026-01-06 17:24:36 -05:00
parent badf8ad486
commit 9e76c1610a

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@@ -53,3 +53,21 @@
\end{enumerate}
By \ref{proposition:fundamental-entourage-criterion}, $\mathfrak{E}$ is a fundamental system of entourages for the uniformity that it generates.
\end{proof}
\begin{definition}[Pointwise Topology]
\label{definition:pointwise}
Let $T$ be a set and $X$ be a topological space, then the following topologies on $X^T$ coincide:
\begin{enumerate}
\item The product topology on $X^T$.
\item The $\mathfrak{S}$-open topology, where $\mathfrak{S} = \bracs{\bracs{x}| x \in X}$.
\item (If $X$ is a uniform space) The $\mathfrak{F}$-uniform topology, where $\fF = \bracs{F| F \subset X \text{ finite}}$.
\end{enumerate}
This topology is the \textbf{topology of pointwise convergence} on $X^T$.
\end{definition}
\begin{proof}
(2) $=$ (3): Let $F \subset X$ finite and $U$ be an entourage, $f \in X^T$, then
\[
E(F, U)(f) = \bigcap_{x \in F}\pi_x^{-1}U(f(x))
\]
which is open in the product topology. The converse is given by \ref{definition:set-uniform}.
\end{proof}