Added the Mackey-Arens theorem.
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@@ -127,3 +127,15 @@
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Therefore $y \in A^{\circ}$, but $\text{Re}\dpn{x_0, y}{\lambda} > 1$, so $x_0 \not\in A^{\circ\circ}$.
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\end{proof}
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\begin{proposition}
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\label{proposition:polar-equicontinuous}
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Let $E$ be a locally convex space, then:
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\begin{enumerate}
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\item For each equicontinuous family $\cf \subset E^*$ equicontinuous, $\cf^\circ \in \cn_E(0)$.
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\item For each $U \in \cn_E(0)$, $U^\circ$ is equicontinuous.
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\end{enumerate}
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\end{proposition}
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