Fixed regex incident.

src/topology/uniform/definition.tex

@@ -41,7 +41,7 @@
         \item[(U1)] For every $U \in \fU$, $U \supset \Delta = \bracs{(x, x)| x \in X}$.
         \item[(U2)] For any $U \in \fU$, $U^{-1} \in \fU$.
         \item[(U3)] For any $U \in \fU$, there exists $V \in \fU$ such that $V \circ V \subset U$.
-    \end\{enumerate\}
+    \end{enumerate}
 
     The elements of $\fU$ are called the \textbf{entourages} of $\fU$, and the pair $(X, \fU)$ is a \textbf{uniform space}.
 
@@ -80,7 +80,7 @@
         \item[(FB1)] For each $U, V \in \fB$, there exists $W \in \fB$ such that $W \subset U \cap V$.
         \item[(UB1)] For each $V \in \fB$, $\Delta \subset V$.
         \item[(UB2)] For each $V \in \fB$, there exists $W \in \fB$ such that $W \circ W \subset V$.
-    \end\{enumerate\}
+    \end{enumerate}
 
     then there exists a unique uniformity $\fU \subset 2^{X \times X}$, which is given by
     \[
@@ -178,7 +178,7 @@ V = (\bracs{x} \times V)(x) = (U \cup (\bracs{x} \times V))(x) = W(x) \in \cn(x)
     \begin{enumerate}
         \item $V \circ M \circ V \in \cn(M)$.
         \item Let $\fB$ be the set of all symmetric entourages, then $\ol{M} = \bigcap_{V \in \fB}V \circ M \circ V$.
-    \end\{enumerate\}
+    \end{enumerate}
 
     with respect to the product topology on $X \times X$.
 \end{proposition}
@@ -226,7 +226,7 @@ V = (\bracs{x} \times V)(x) = (U \cup (\bracs{x} \times V))(x) = W(x) \in \cn(x)
     \begin{enumerate}
         \item $\mathfrak{O} = \bracs{U^o| U \in \fU}$
         \item $\mathfrak{K} = \bracsn{\overline{U}| U \in \fU}$.
-    \end\{enumerate\}
+    \end{enumerate}
 
     By \autoref{lemma:symmetricfundamentalentourage}, there exists fundamental systems of entourages for $\fU$ consisting of symmetric and open/closed sets.
 \end{proposition}
@@ -271,7 +271,7 @@ V = (\bracs{x} \times V)(x) = (U \cup (\bracs{x} \times V))(x) = W(x) \in \cn(x)
         \item $X$ is Hausdorff.
         \item $X$ is regular.
         \item $\Delta = \bigcap_{U \in \fU}U$.
-    \end\{enumerate\}
+    \end{enumerate}
 
     If the above holds, then $X$ is \textbf{separated}.
 \end{definition}