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@@ -18,6 +18,17 @@
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For each $x \in A$, let $L_x \in L(A; A)$ be defined by $y \mapsto xy$, and let $\norm{x}_1 = \norm{L_x}_{L(A; A)}$, then $\norm{x}_1 \le \norm{x}_A$ and $\norm{1}_1 = 1$. On the other hand, $\frac{\norm{x}_A}{\norm{1}_A} \le \norm{x}_1$, so $\norm{\cdot}_1$ is equivalent to $\norm{\cdot}_A$.
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\end{proof}
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\begin{definition}[Centre]
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\label{definition:banach-algebra-centre}
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Let $A$ be a Banach algebra, then
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\[
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Z(A) = \bracsn{x \in A|xy = yx \forall y \in A}
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\]
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is the \textbf{centre} of $A$.
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\end{definition}
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\begin{definition}[Homomorphism]
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\label{definition:banach-algebra-homomorphism}
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Let $A, B$ be Banach algebras and $\phi: A \to B$, then $\phi$ is a \textbf{homomorphism} if:
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