Added preimage functions.
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@@ -68,6 +68,12 @@
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(2) $\Rightarrow$ (3): Since $\fF$ is Cauchy, there exists $\seq{E_n} \subset \fF$ such that for each $n \in \natp$, $E_n \supset E_{n+1}$ and $\sup_{y, z \in E_n}d(y, z) \le 1/n$. For each $n \in \natp$, let $x_n \in E_n$, then there exists a subsequence $\seq{n_k}$ and $x \in X$ such that $x = \limv{n}x_n$. In which case, $x \in \bigcap_{n \in \natp}\overline{E_n}$. For each $n \in \natp$, $\sup_{y, z\in E_n}d(y, z) \le 1/n$, so $B_X(x, 2/n) \supset E_n$. Therefore $\fF \to x$.
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\end{proof}
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\begin{definition}[Polish Space]
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\label{definition:polish-space}
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Let $X$ be a topological space, then $X$ is \textbf{Polish} if it is completely metrisable and second countable.
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\end{definition}
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\begin{theorem}[Banach's Fixed Point Theorem]
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\label{theorem:banach-fixed-point}
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@@ -98,3 +104,6 @@
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\]
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\end{proof}
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