Adjusted mean value theorem.

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Bokuan Li
2026-02-03 11:07:32 -05:00
parent 04786ba3d9
commit 7bbbf75213
3 changed files with 31 additions and 9 deletions

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@@ -143,11 +143,12 @@
Let $E$ be a separated topological vector space and $\sigma \subset B(\real)$ be an upward-directed system that contains finite sets, then
\begin{enumerate}
\item $\mathcal{R}_{\sigma}(\real; E) = \mathcal{R}_{B(\real)}(\real; E)$. Hence, all forms of $\sigma$-differentiability on $\real$ are equivalent.
\item For any $U \subset \real$ open, $f: U \to E$, and $x_0 \in U$, $f$ is ($\sigma$-)differentiable at $x_0$ if and only if
\item For any $U \subset \real$ open, $f: U \to E$, and $x_0 \in U$, $f$ is differentiable at $x_0$ if and only if
\[
\lim_{t \to 0}\frac{f(x + t) - f(x)}{t}
\]
exists. In which case, the above limit is identified with the ($\sigma$-)derivative of $f$ at $0$.
exists. In which case, the above limit is identified with the derivative of $f$ at $0$.
\item For any $U \subset \real$ open, $f: U \to E$, and $x_0 \in U$, if $f$ is differentiable at $x_0$, then $f$ is continuous at $x_0$.
\end{enumerate}
\end{proposition}
\begin{proof}