Enforced Borel sigma algebra convention.
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@@ -5,7 +5,8 @@
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\input{./src/measure/measure/complete.tex}
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\input{./src/measure/measure/semifinite.tex}
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\input{./src/measure/measure/sigma-finite.tex}
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\input{./src/measure/measure/outer.tex}
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\input{./src/measure/measure/regular.tex}
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\input{./src/measure/measure/radon.tex}
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\input{./src/measure/measure/outer.tex}
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\input{./src/measure/measure/lebesgue-stieltjes.tex}
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\input{./src/measure/measure/kolmogorov.tex}
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12
src/measure/measure/radon.tex
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12
src/measure/measure/radon.tex
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\section{Radon Measures}
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\label{section:radon-measure}
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\begin{definition}[Radon Measure]
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\label{definition:radon-measure}
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Let $X$ be a LCH space and $\mu: \cb(X) \to [0, \infty]$ be a Borel measure, then $\mu$ is a \textbf{Radon measure} if:
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\begin{enumerate}
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\item For any $K \subset X$ compact, $\mu(K) < \infty$.
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\item $\mu$ is outer regular on all Borel sets.
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\item $\mu$ is inner regular on all open sets.
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\end{enumerate}
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\end{definition}
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@@ -3,7 +3,7 @@
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\begin{definition}[Inner Regular]
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\label{definition:inner-regular}
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Let $X$ be a topological space and $\mu: \cb_X \to [0, \infty]$ be a measure, then $\mu$ is \textbf{inner regular} if for any $E \in \cb_X$,
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Let $X$ be a topological space, $\mu: \cb_X \to [0, \infty]$ be a Borel measure, and $E \in \cb_X$, then $\mu$ is \textbf{inner regular} on $E$ if
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\[
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\mu(E) = \sup\bracs{\mu(K)| K \subset E, K \text{ compact}}
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\]
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@@ -11,7 +11,7 @@
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\begin{definition}[Outer Regular]
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\label{definition:outer-regular}
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Let $X$ be a topological space and $\mu: \cb_X \to [0, \infty]$ be a measure, then $\mu$ is \textbf{outer regular} if for any $E \in \cb_X$,
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Let $X$ be a topological space, $\mu: \cb_X \to [0, \infty]$ be a Borel measure, and $E \in \cb_X$, then $\mu$ is \textbf{outer regular} on $E$ if
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\[
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\mu(E) = \sup\bracs{\mu(U)| U \supset A, U \text{ open}}
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\]
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@@ -19,7 +19,7 @@
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\begin{definition}[Regular]
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\label{definition:regular-measure}
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Let $X$ be a topological space and $\mu: \cb_X \to [0, \infty]$ be a measure, then $\mu$ is \textbf{regular} if it is inner regular and outer regular.
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Let $X$ be a topological space and $\mu: \cb_X \to [0, \infty]$ be a measure, then $\mu$ is \textbf{regular} if it is inner regular and outer regular on all Borel sets.
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\end{definition}
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\begin{theorem}[{{\cite[Theorem 7.8]{Folland}}}]
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