First draft of L^1.
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\end{align*}
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which contradicts the fact that $\lambda \ne 1$. Therefore $\lambda = 1$, and $\nu(dx) = \Delta_G(x^{-1})\mu(dx)$.
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\end{proof}
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\begin{definition}[Unimodular]
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\label{definition:lcg-unimodular}
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Let $G$ be a locally compact group, then $G$ is \textbf{unimodular} if $\Delta_G = 1$.
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\end{definition}
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