First draft of L^1.

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Bokuan Li
2026-09-19 20:57:32 -04:00
parent c05faf4a77
commit 6414c49ab3
3 changed files with 320 additions and 34 deletions
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@@ -42,8 +42,12 @@
\end{align*}
which contradicts the fact that $\lambda \ne 1$. Therefore $\lambda = 1$, and $\nu(dx) = \Delta_G(x^{-1})\mu(dx)$.
\end{proof}
\begin{definition}[Unimodular]
\label{definition:lcg-unimodular}
Let $G$ be a locally compact group, then $G$ is \textbf{unimodular} if $\Delta_G = 1$.
\end{definition}