Added Urysohn Metrisation theorem and compactness theorems.
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Bokuan Li
2026-05-26 19:32:02 -04:00
parent f6c5976873
commit 5923b45f9d
9 changed files with 208 additions and 57 deletions

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@@ -3,7 +3,7 @@
\begin{definition}[Metric Space]
\label{definition:metric}
Let $X$ be a set and $d: X \times X$, then $d$ is a \textbf{metric} if:
Let $X$ be a set and $d: X \times X \to [0, \infty]$, then $d$ is a \textbf{metric} if:
\begin{enumerate}
\item[(PM1)] For any $x \in X$, $d(x, x) = 0$.
\item[(M)] For any $x, y \in X$ with $x \ne y$, $d(x, y) > 0$.
@@ -41,10 +41,23 @@
(3) $\Rightarrow$ (1): Let $\seq{x_n} \subset X$ be a countable dense subset. Let $x \in X$ and $k \in \natp$, then there exists $x_n \in \natp$ such that $d(x, x_n) < 1/(2k)$. In which case, $x \in B(x_n, 1/(2k)) \subset B(x_n, 1/k)$. Therefore $\bracs{B(x_n, 1/k)|n, k \in \natp}$ forms a countable basis for $X$.
\end{proof}
\begin{proposition}
\label{proposition:countable-metric}
Let $\seq{(X_n, d_n)}$ be metrisable spaces, then $\prod_{n \in \natp}X_n$ is also metrisable.
\end{proposition}
\begin{proof}
For each $n \in \natp$, let
\[
d_n': \braks{\prod_{n \in \natp}X_n}^2 \to [0, \infty] \quad (x, y) \mapsto d_n(\pi_n(x), \pi_n(y))
\]
then $d_n'$ is a pseudometric on $X$, and $\bracsn{d_n'}_1^\infty$ induces the product uniformity on $\prod_{n \in \natp}X_n$. By \autoref{theorem:uniform-metrisable}, $\prod_{n \in \natp}X_n$ is also metrisable.
\end{proof}
\begin{theorem}[Banach's Fixed Point Theorem]
\label{theorem:banach-fixed-point}
Let $(X, d)$ be a metric space and $f: X \to X$. If there exists $C \in (0, 1)$ such that
Let $(X, d)$ be a complete metric space and $f: X \to X$. If there exists $C \in (0, 1)$ such that
\[
d(f(x), f(y)) \le Cd(x, y) \quad \forall x, y \in X
\]