Removed typo
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@@ -106,7 +106,7 @@
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\begin{proof}
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(2) $=$ (3): Let $F \subset X$ finite and $U$ be an entourage, $f \in X^T$, then
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\[
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E(F, U)(f) = \bigcap_{x \in F}\pi_x^{-1}U(f(x))
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E(F, U)(f) = \bigcap_{x \in F}\pi_x^{-1}(U(f(x)))
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\]
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which is open in the product topology. The converse is given by \ref{definition:set-uniform}.
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\end{proof}
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