Cleanup

src/fa/tvs/bounded.tex

@@ -20,16 +20,18 @@
 \begin{proof}
     Let $U \in \cn(0)$.
 
-    (2): Using \ref{proposition:uniform-neighbourhoods}, assume without loss of generality that $U$ is closed. Let $0 \ne \lambda \in K$ with $\lambda U \supset B$, then since $\lambda U$ is closed, $\lambda U \supset \ol B$.
+    (2): Using \autoref{proposition:uniform-neighbourhoods}, assume without loss of generality that $U$ is closed. Let $0 \ne \lambda \in K$ with $\lambda U \supset B$, then since $\lambda U$ is closed, $\lambda U \supset \ol B$.
 
-    (4), (5): By \ref{proposition:tvs-good-neighbourhood-base}, there exists $V \in \cn(0)$ circled such that $V + V \subset U$, and $\lambda, \lambda' \in K$ such that $\lambda V \supset A$ and $\lambda' V \supset B$.
+    (4), (5): By \autoref{proposition:tvs-good-neighbourhood-base}, there exists $V \in \cn(0)$ circled such that $V + V \subset U$, and $\lambda, \lambda' \in K$ such that $\lambda V \supset A$ and $\lambda' V \supset B$.
 
     Let $\mu > \abs{\lambda}, \abs{\lambda'}$, then
     \[
     \mu U \supset \mu V \supset \lambda V \cup \lambda' V \supset A \cup B
     \]
+
     and
     \[
     \mu U \supset \mu(V + V) \supset \lambda V + \lambda' V \supset A + B
     \]
+
 \end{proof}