Cleanup

src/cat/tricks/product.tex

@@ -7,10 +7,12 @@
     \[
     ab \le \frac{a^p}{p} + \frac{b^q}{q}
     \]
+
     and for any $\eps > 0$,
     \[
     ab \le \eps a^p + \frac{1}{q}(\eps q)^{-q/p}b^q
     \]
+
 \end{lemma}
 \begin{proof}
     Since $x \mapsto \exp(x)$ is convex,
@@ -22,4 +24,5 @@
     \[
     ab = (\eps p)^{1/p}a \cdot \frac{b}{(\eps p)^{1/p}} \le \eps a^p + \frac{b^q}{q}(\eps p)^{-(1/p)q} = \eps a^p + \frac{1}{q}(\eps q)^{-q/p}b^q
     \]
+
 \end{proof}