Adjusted formulation of a total variation statement.
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@@ -23,7 +23,7 @@
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$(3) \Rightarrow (2)$: Let $D \subset E$ be a barrel and $\rho: E \to [0, \infty)$ be its gauge. By (4) of \autoref{definition:gauge}, $D = \bracs{\rho \le 1}$, so $\bracs{\rho > 1}$ is open, and $\rho$ is semicontinuous. By assumption, $\rho$ is continuous, so $D \in \cn_E(0)$ by (5) of \autoref{lemma:continuous-seminorm}.
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\end{proof}
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\begin{summary}[Barreled Spaces]
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\begin{summary}
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\label{summary:barreled-space}
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The following types of locally convex spaces are barreled:
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\begin{enumerate}
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@@ -61,7 +61,7 @@
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\label{proposition:barrel-limit}
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Let $\seqi{E}$ be locally convex spaces over $K \in \RC$, $E$ be a vector space over $K$, and $\seqi{T}$ such that $T_i \in \hom(E_i; E)$ for all $i \in I$, then the inductive locally convex topology on $E$ induced by $\seqi{T}$ is barreled.
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\end{proposition}
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\begin{proof}[Proof, {{\cite[II.7.2]{SchaeferWolff}}}]
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\begin{proof}[Proof, {{\cite[II.7.2]{SchaeferWolff}}}. ]
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Let $D \subset E$ be a barrel, then for each $i \in I$, $T_i^{-1}(D) \subset E_i$ is also a barrel, and thus a neighbourhood of $0$ in $E_i$. By (5) of \autoref{definition:lc-inductive}, $D$ is a neighbourhood of $0$ in $E$, so $E$ is barreled.
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\end{proof}
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@@ -65,7 +65,7 @@
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\begin{enumerate}
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\item $BV([a, b]; E)$ is a vector space.
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\item For each continuous seminorm $\rho$ on $E$, $[\cdot]_{\text{var}, \rho}$ is a seminorm on $BV([a, b]; E)$.
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\item For each continuous seminorm $\rho$ on $E$ and $M > 0$, $\bracs{[\cdot]_{\text{var}, \rho} \le M} \subset E^{[a, b]}$ is closed.
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\item For each continuous seminorm $\rho$ on $E$, $[\cdot]_{\text{var}, \rho}: E^{[a, b]} \to [0, \infty]$ is lower semicontinuous. In particular, for any $M > 0$, $\bracs{[\cdot]_{\text{var}, \rho} \le M} \subset E^{[a, b]}$ is closed.
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\item For any $f \in BV([a, b]; E)$ and continuous seminorm $\rho$ on $E$, $\sup_{x \in [a, b]}\rho(f(x)) \le \rho(f(a)) + [f]_{\text{var}, \rho}$.
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\end{enumerate}
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If $(E, \norm{\cdot}_E)$ is a normed vector space, then
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@@ -74,16 +74,6 @@
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\end{enumerate}
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\end{definition}
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\begin{proof}[Proof {{\cite[Proposition X.1.1]{Lang}}}. ]
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(3): Let $\rho$ be a continuous seminorm on $E$, $P = \seqf{x_j} \in \scp([a, b])$, and $f \in \overline{\bracs{[\cdot]_{\text{var}, \rho} \le M}}$. For any $\eps > 0$, there exists $g \in \bracs{[\cdot]_{\text{var}, \rho} \le M}$ such that $\rho(f(x_j) - g(x_j)) < \eps$ for each $1 \le j \le n$. In which case,
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\begin{align*}
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V_{\rho, P}(f) &= \sum_{j = 1}^n \rho(f(x_j) - f(x_{j - 1})) \\
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&\le 2n\eps + \sum_{j = 1}^n \rho(g(x_j) - g(x_{j - 1})) \\
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&\le V_{\rho, P}(g) + 2n\eps \le M + 2n\eps
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\end{align*}
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As the above holds for all $\eps > 0$, $V_{\rho, P}(f) \le M$. Since this holds for all $P \in \scp([a, b])$, $[f]_{\text{var}, \rho} \le M$.
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(5): For each $n \in \nat^+$, let
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\[
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D_n = \bracs{x \in [a, b]|\forall \eps > 0, \exists y \in (x - \eps, x + \eps): \norm{f(x) - f(y)}_E \ge 1/n}
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