diff --git a/src/op/system/two.tex b/src/op/system/two.tex index 03f5029..95d9af6 100644 --- a/src/op/system/two.tex +++ b/src/op/system/two.tex @@ -1,4 +1,4 @@ -\section{On the Subject of 2×2 Matrices} +\section{On 2×2 Matrices} \label{section:op-sys-2by2} \begin{lemma} @@ -194,7 +194,7 @@ \item $\left[\begin{smallmatrix} P & A \\ A^* & Q \end{smallmatrix}\right] \ge 0$. \item For each $\xi, \eta \in H$, $|\dpn{A\xi, \eta}{H}| \le \dpn{Q\xi, \xi}{H}^{1/2}\dpn{P\eta, \eta}{H}^{1/2}$. \item $P \ge 0$, $A(H) \subset P^{1/2}(H)$, and $Q - (P^{-1/2}A)^*(P^{-1/2}A) \ge 0$. - \item $Q \ge 0$, $A^*(H) \subset Q^{1/2}(H)$, and $P - (Q^{-1/2}A)^*(Q^{-1/2}A) \ge 0$. + \item $Q \ge 0$, $A^*(H) \subset Q^{1/2}(H)$, and $P - (Q^{-1/2}A^*)^*(Q^{-1/2}A^*) \ge 0$. \end{enumerate} \end{proposition} \begin{proof}[Proof, {{\cite[Exercise 3.2]{Paulsen}}}. ] @@ -267,7 +267,7 @@ so \[ - 0 \le Q - (P^{-1/2}A)^*(P^{1/2}A) \le Q - A^*(P+\eps)^{-1}A + 0 \le Q - (P^{-1/2}A)^*(P^{-1/2}A) \le Q - A^*(P+\eps)^{-1}A \] and $\left[\begin{smallmatrix} P + \eps & A \\ A^* & Q \end{smallmatrix}\right] \ge 0$ by (P2) of \autoref{proposition:schur-complement-positive}. As this holds for all $\eps > 0$, $\left[\begin{smallmatrix} P& A \\ A^* & Q \end{smallmatrix}\right] \ge 0$. @@ -310,8 +310,8 @@ and \begin{align*} - \dpn{A + A^*\xi, \xi}{H} &= 2\text{Re}\dpn{A + A^*\xi, \xi}{H} \\ - |\dpn{A + A^*\xi, \xi}{H}| &\le 2 \dpn{P\xi, \xi}{H}^{1/2}\dpn{Q\xi, \xi}{H}^{1/2} \\ + \dpn{(A + A^*)\xi, \xi}{H} &= 2\text{Re}\dpn{A + A^*\xi, \xi}{H} \\ + |\dpn{(A + A^*)\xi, \xi}{H}| &\le 2 \dpn{P\xi, \xi}{H}^{1/2}\dpn{Q\xi, \xi}{H}^{1/2} \\ \dpn{(P + A + A^* + Q)\xi, \xi}{H} &\le \dpn{P\xi, \xi}{H} + 2 \dpn{P\xi, \xi}{H}^{1/2}\dpn{Q\xi, \xi}{H}^{1/2} + \dpn{Q\xi, \xi}{H} \\ &= (\dpn{P\xi, \xi}{H}^{1/2} + \dpn{Q\xi, \xi}{H}^{1/2})^2 \\ \end{align*} @@ -339,7 +339,7 @@ In particular, for $\xi = -A\eta/\norm{P}_{B(H)}$, \begin{align*} 0 &\le \frac{\dpn{PA\eta, A\eta}{H}}{\norm{P}_{B(H)}^2} + \dpn{P\eta, \eta}{H} - \frac{\dpn{A\eta, A\eta}{H}}{\norm{P}_{B(H)}} - \frac{\dpn{A^*A\eta, \eta}{H}}{\norm{P}_{B(H)}} \\ - &= \frac{\dpn{PA\eta, A\eta}{H}}{\norm{P}_{B(H)}} + \norm{P}_{B(H)}\dpn{P\eta, \eta}{H} - 2\norm{A\eta}_H^2 \\ + 0 &\le \frac{\dpn{PA\eta, A\eta}{H}}{\norm{P}_{B(H)}} + \norm{P}_{B(H)}\dpn{P\eta, \eta}{H} - 2\norm{A\eta}_H^2 \\ &\le\norm{A\eta}_H^2 + \norm{P}_{B(H)}\dpn{P\eta, \eta}{H} - 2\norm{A\eta}_H^2 \\ &= \norm{P}_{B(H)}\dpn{P\eta, \eta}{H} - \dpn{A^*A\eta, \eta}{H} \end{align*}