From 39e967c1985c6d9e5404fe31f40458f3149b28b2 Mon Sep 17 00:00:00 2001 From: Bokuan Li <47512608+Jerry-licious@users.noreply.github.com> Date: Thu, 8 Jan 2026 23:01:27 -0500 Subject: [PATCH] Reorganised the completion of uniform spaces. --- src/topology/uniform/cauchy.tex | 0 src/topology/uniform/complete.tex | 18 ++++++++++++------ src/topology/uniform/completion.tex | 4 ++-- src/topology/uniform/index.tex | 1 + 4 files changed, 15 insertions(+), 8 deletions(-) create mode 100644 src/topology/uniform/cauchy.tex diff --git a/src/topology/uniform/cauchy.tex b/src/topology/uniform/cauchy.tex new file mode 100644 index 0000000..e69de29 diff --git a/src/topology/uniform/complete.tex b/src/topology/uniform/complete.tex index de29d20..80f79cd 100644 --- a/src/topology/uniform/complete.tex +++ b/src/topology/uniform/complete.tex @@ -33,12 +33,18 @@ Let $x \in X$ such that $\cn(x) \subset \fF$ and $V \in \fU$. By \ref{lemma:symmetricfundamentalentourage}, assume without loss of generality that $V \in \fU$. Since $\cn(x) \subset \fF$, then $V(x) \in \fU$ and $V(x) \times V(x) \subset V$. \end{proof} +\begin{definition}[Cauchy Continuous] +\label{definition:cauchy-continuous} + Let $X, Y$ be uniform spaces and $f: X \to Y$, then $f$ is \textbf{Cauchy continuous} if for any Cauchy filter base $\fB \subset 2^X$, $f(\fB) \subset 2^Y$ is Cauchy. +\end{definition} + + \begin{proposition}[{{\cite[Proposition 2.3.3]{Bourbaki}}}] \label{proposition:imagecauchy} - Let $(X, \fU)$ and $(Y, \mathfrak{V})$ be uniform spaces, $f \in UC(X; Y)$, and $\fB \subset 2^X$ be a Cauchy filter base, then $f(\fB) \subset 2^Y$ is a Cauchy filter base. + Let $(X, \fU)$ and $(Y, \mathfrak{V})$ be uniform spaces and $f \in UC(X; Y)$, then $f$ is Cauchy continuous. \end{proposition} \begin{proof} - Let $V \in \mathfrak{V}$, then there exists $V' \in \fU$ such that $(f(x), f(y)) \in V$ whenever $(x, y) \in V'$. Given that $\fB$ is a Cauchy filter base, there exists $E \in \fB$ such that $E \times E \subset V'$, so $f(E) \times f(E) \subset V$. + Let $V \in \mathfrak{V}$, then there exists $V' \in \fU$ such that $(f(x), f(y)) \in V$ whenever $(x, y) \in V'$. For any Cauchy filter base $\fB \subset 2^X$, there exists $E \in \fB$ such that $E \times E \subset V'$, so $f(E) \times f(E) \subset V$. \end{proof} \begin{definition}[Minimal Cauchy Filter] @@ -131,7 +137,7 @@ Let $X$ be a topological space, $Y$ be a complete Hausdorff uniform space, $A \subset X$ be a dense subset, and $f \in C(A; Y)$ be a continuous function, then the following are equivalent: \begin{enumerate} \item There exists a continuous function $F \in C(X; Y)$ such that $F|_A = f$. - \item For each $x \in X$, $f(\bracs{U \cap A| U \in \cn(x)})$ is a Cauchy filter base. + \item $f$ is Cauchy continuous. \end{enumerate} \end{proposition} \begin{proof} @@ -141,10 +147,10 @@ \begin{theorem}[Extension of Uniformly Continuous Functions, {{\cite[Theorem 1.3.2]{Bourbaki}}}] \label{theorem:uniform-continuous-extension} - Let $(X, \fU)$, $(Y, \fV)$ be uniform spaces, $A \subset Y$ be a dense subset, and $f \in UC(A; Y)$, then: + Let $(X, \fU)$ be a uniform space, $(Y, \fV)$ be a complete Hausdorff uniform space, $A \subset Y$ be a dense subset, and $f \in C(A; Y)$ be Cauchy continuous, then: \begin{enumerate} - \item There exists a unique $F \in UC(X; Y)$ such that $F|_A = f$. - \item $F \in UC(X; Y)$. + \item There exists a unique $F \in C(X; Y)$ such that $F|_A = f$. + \item If $f \in UC(A; Y)$, then $F \in UC(X; Y)$. \end{enumerate} \end{theorem} \begin{proof} diff --git a/src/topology/uniform/completion.tex b/src/topology/uniform/completion.tex index dce0efd..cb6dd29 100644 --- a/src/topology/uniform/completion.tex +++ b/src/topology/uniform/completion.tex @@ -8,7 +8,7 @@ \begin{enumerate} \item $(\wh X, \wh \fU)$ is a complete Hausdorff uniform space. \item $\iota \in UC(X; \wh X)$. - \item[(U)] For any pair $(Y, f)$ satisfying (1) and (2), there exists unique $F \in C(\wh X; Y)$ such that the following diagram commutes + \item[(U)] For any complete Hausdorff uniform space $Y$ and Cauchy continuous function $f: X \to Y$, there exists unique $F \in C(\wh X; Y)$ such that the following diagram commutes \[ \xymatrix{ @@ -17,7 +17,7 @@ } \] - and $F \in UC(\wh X; Y)$. + Moreover, if $f \in UC(X; Y)$, then $F \in UC(\wh X; Y)$. \end{enumerate} Moreover, \begin{enumerate} diff --git a/src/topology/uniform/index.tex b/src/topology/uniform/index.tex index a3bb6a7..9001d95 100644 --- a/src/topology/uniform/index.tex +++ b/src/topology/uniform/index.tex @@ -3,5 +3,6 @@ \input{./src/topology/uniform/definition.tex} \input{./src/topology/uniform/uc.tex} +\input{./src/topology/uniform/cauchy.tex} \input{./src/topology/uniform/complete.tex} \input{./src/topology/uniform/completion.tex}