Added the Bochner integral.
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@@ -86,3 +86,17 @@
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so $\sup_{T \in \mathcal{T}}\norm{T}_{L(E; F)} \le 2n/r$.
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\end{proof}
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\begin{proposition}
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\label{proposition:dual-norm}
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Let $E$ be a normed space, then for any $x \in E$,
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\[
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\norm{x}_E = \sup_{\substack{\phi \in E^* \\ \norm{\phi}_{E^*} = 1}}\dpn{x, \phi}{E}
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\]
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\end{proposition}
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\begin{proof}
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For any $\phi \in E^*$ with $\norm{\phi}_{E^*} = 1$, $\dpn{x, \phi}{E} \le \norm{x}_E \cdot \norm{\phi}_{E^*} = \norm{x}_E$. On the other hand, by the \hyperref[Hahn-Banach Theorem]{proposition:hahn-banach-utility}, there exists $x \in E^*$ such that $\dpn{x, \phi}{E} = \norm{x}_E$ and $\norm{\phi}_{E^*} \le 1$.
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\end{proof}
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