Added the continuous functional calculus.
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src/op/c-star/cont.tex
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src/op/c-star/cont.tex
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\section{The Continuous Functional Calculus}
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\label{section:continuous-functional-calculus}
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\begin{theorem}[Spectral Theorem for $C^*$-Algebras]
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\label{theorem:spectral-c-star}
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Let $A$ be a unital $C^*$-algebra and $x \in A$ be normal, then the mapping
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\[
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\Phi: \Omega(A[x]) \to \sigma_A(x) \quad \Phi(\psi) = \Gamma_{A[x]}(x)(\psi) = \psi(x)
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\]
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is a homeomorphism.
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\end{theorem}
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\begin{proof}
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Firstly, $A[x]$ is commutative by \autoref{proposition:generated-subalgebra-dense}. Thus \autoref{corollary:c-star-algebra-preserve-spectrum} and (3) of \autoref{proposition:gelfand-transform-gymnastics} imply that
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\[
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\Phi(\Omega(A[x])) = \Gamma_{A[x]}(\Omega(A[x])) = \sigma_{A[x]}(x) = \sigma_A(x)
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\]
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and $\Phi$ is a surjection onto $\sigma_A(x)$.
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On the other hand, the \hyperref[Gelfand-Naimark Theorem]{theorem:gelfand-naimark} implies that $\Phi(x^*) = \ol{\Phi(x)}$, so since $A[x]$ is the smallest $C^*$-algebra containing $x$, any element $\psi \in \Omega(A[x])$ is uniquely determined by $\psi(x)$. Therefore $\Phi$ is injective.
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Finally, since $\Omega(A[x])$ is equipped with the weak* topology and $\Phi$ is the evaluation map at $x$, it is continuous.
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By \autoref{proposition:compact-hausdorff-homeomorphism}, $\Phi$ is a homeomorphism.
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\end{proof}
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\begin{definition}[Continuous Functional Calculus]
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\label{definition:continuous-functional-calculus}
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Let $A$ be a unital $C^*$-algebra and $x \in A$ be normal, then there exists a unique continuous unital *-homomorphism
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\[
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C(\sigma_A(x); \complex) \to A[x] \quad f \mapsto f(x)
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\]
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such that:
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\begin{enumerate}
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\item $\one(x) = 1_A$.
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\item $\text{Id}(x) = x$.
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\item $\overline{\text{Id}}(x) = x^*$.
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\end{enumerate}
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Moreover,
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\begin{enumerate}[start=3]
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\item Under the identification $\Omega(A[x]) = \sigma_A(x)$, for each $f \in C(\sigma_A(x); \complex)$, $f(x) = \Gamma^{-1}_{A[x]}(f)$.
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\item The mapping $f \mapsto f(x)$ is a unital *-isomorphism.
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\end{enumerate}
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\end{definition}
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\begin{proof}
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(1), (4), (5): By the \hyperref[Spectral Theorem]{theorem:spectral-c-star}, $\Omega(A[x])$ and $\sigma_A(x)$ may be identified. For each $f \in C(\sigma_A(x); \complex)$, define $f(x) = \Gamma^{-1}_{A[x]}(f)$, then the mapping $f \mapsto f(x)$ is a unital *-isomorphism by the \hyperref[Gelfand-Naimark Theorem]{theorem:gelfand-naimark}.
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(2): The identification
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\[
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\Phi: \Omega(A[x]) \to \sigma_A(x) \quad \Phi(\psi) = \Gamma_{A[x]}(x)(\psi) = \psi(x)
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\]
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given by the Spectral Theorem implies that $\Gamma_{A[x]}(x) = \text{Id}$.
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(3): The mapping $f \mapsto f(x)$ is a *-homomorphism.
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(Uniqueness): By the \hyperref[Stone-Weierstrass Theorem]{theorem:complex-stone-weierstrass}.
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\end{proof}
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@@ -2,8 +2,10 @@
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\label{chap:c-star-algebras}
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\input{./involution.tex}
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\input{./sub.tex}
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\input{./unitary.tex}
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\input{./sa.tex}
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\input{./order.tex}
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\input{./homomorphism.tex}
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\input{./gelfand.tex}
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\input{./gelfand.tex}
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\input{./cont.tex}
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@@ -41,17 +41,4 @@
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(3): For any $x \in A$, $(x^{-1})^*x^* = (x^{-1}x)^* = 1 = (xx^{-1})^* = x^*(x^{-1})^*$.
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\end{proof}
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\begin{definition}[*-Homomorphism]
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\label{definition:star-homomorphism}
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Let $A, B$ be $C^*$-algebras and $\phi: A \to B$, then $\phi$ is a \textbf{*-homomorphism} if:
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\begin{enumerate}
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\item $\phi$ is a homomorphism of Banach algebras.
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\item For every $x \in A$, $\phi(x^*) = \phi(x)^*$.
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\end{enumerate}
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If in addition, $\phi(1) = 1$, then $\phi$ is a \textbf{unital *-homomorphism}.
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\end{definition}
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41
src/op/c-star/sub.tex
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src/op/c-star/sub.tex
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\section{Subalgebras}
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\label{section:sub-c-star-algebras}
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\begin{definition}[Generated Subalgebra]
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\label{definition:generated-subalgebra}
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Let $A$ be a unital $C^*$-algebra and $S \subset A$, then $A[S]$ is the smallest $C^*$-subalgebra of $A$ containing $1$ and $S$.
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\end{definition}
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\begin{proposition}
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\label{proposition:generated-subalgebra-dense}
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Let $A$ be a unital $C^*$-algebra, $S \subset A$, and $\mathcal{S} = S \cup \bracs{x^*|x \in S}$, then
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\begin{enumerate}
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\item The linear span
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\[
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\text{span}\bracs{\prod_{j = 1}^n x_j \bigg | \seqf{x_j} \subset \mathcal{S}}
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\]
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is dense in $A[S]$.
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\item If for any $x, y \in \mathcal{S}$, $xy = yx$, then $A[S]$ is commutative.
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\item For any normal element $x \in A$, $A[x]$ is commutative.
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\end{enumerate}
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\end{proposition}
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% Obvious so omitted.
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\begin{proposition}
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\label{proposition:c-star-algebra-preserve-gl}
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Let $A$ be a unital $C^*$-algebra, $B \subset A$ be a $C^*$-subalgebra containing $1$, then $G(B) = G(A) \cap B$.
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\end{proposition}
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\begin{proof}
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Let $x \in G(A) \cap B$, then $x^*x \in G(A) \cap B$ as well. In particular, $0 \not\in \sigma_A(x^*x)$. Since $x^*x \in A_{sa}$, $\sigma_A(x^*x) \subset \real$ by \autoref{proposition:self-adjoint-spectrum}. By \autoref{proposition:spectrum-subalgebra-gymnastics}, $\partial \sigma_B(x^*x) \subset \sigma_A(x^*x) \subset \real$. Thus $\sigma_B(x^*x) \subset \real$ as well, which means that $\partial \sigma_B(x^*x) = \sigma_B(x^*x) = \sigma_A(x^*x)$. Therefore $0 \not\in \sigma_A(x^*x) = \sigma_B(x^*x)$, $x^*x \in G(B)$, and $x \in G(B)$.
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\end{proof}
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\begin{corollary}
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\label{corollary:c-star-algebra-preserve-spectrum}
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Let $A$ be a unital $C^*$-algebra, $B \subset A$ be a $C^*$-subalgebra containing $1$, and $x \in B$, then $\sigma_A(x) = \sigma_B(x)$.
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\end{corollary}
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\begin{proof}
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By \autoref{proposition:c-star-algebra-preserve-gl}.
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\end{proof}
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