From 234f1586636f1a3afc84b543828435fd33492225 Mon Sep 17 00:00:00 2001 From: Bokuan Li Date: Thu, 22 Jan 2026 18:47:33 -0500 Subject: [PATCH] Added quotient topology. --- src/measure/lebesgue-integral/complex.tex | 0 src/topology/main/index.tex | 1 + src/topology/main/quotient.tex | 46 +++++++++++++++++++++++ 3 files changed, 47 insertions(+) create mode 100644 src/measure/lebesgue-integral/complex.tex create mode 100644 src/topology/main/quotient.tex diff --git a/src/measure/lebesgue-integral/complex.tex b/src/measure/lebesgue-integral/complex.tex new file mode 100644 index 0000000..e69de29 diff --git a/src/topology/main/index.tex b/src/topology/main/index.tex index 97affde..9130c6a 100644 --- a/src/topology/main/index.tex +++ b/src/topology/main/index.tex @@ -11,6 +11,7 @@ \input{./src/topology/main/hausdorff.tex} \input{./src/topology/main/regular.tex} \input{./src/topology/main/normal.tex} +\input{./src/topology/main/quotient.tex} \input{./src/topology/main/unity.tex} \input{./src/topology/main/compact.tex} \input{./src/topology/main/sigma-compact.tex} diff --git a/src/topology/main/quotient.tex b/src/topology/main/quotient.tex new file mode 100644 index 0000000..e1ace76 --- /dev/null +++ b/src/topology/main/quotient.tex @@ -0,0 +1,46 @@ +\section{Quotient Topologies} +\label{section:quotient-topology} + +\begin{definition}[Saturated] +\label{definition:saturated} + Let $X, Y$ be sets, $f: X \to Y$ be surjective, and $E \subset X$, then $E$ is \textbf{saturated} with respect to $f$ if $E = f^{-1}(f(E))$. +\end{definition} + +\begin{definition}[Quotient Map] +\label{definition:quotient-map} + Let $X, Y$ be topological spaces and $\pi: X \to Y$ be a surjective map, then the following are equivalent: + \begin{enumerate} + \item For any $U \subset Y$, $U$ is open if and only if $\pi^{-1}(U)$ is open. + \item $\pi \in C(X; Y)$, and for any $U \subset X$ saturated and open, $\pi(U)$ is open. + \end{enumerate} + If the above holds, then $\pi$ is a \textbf{quotient map}. +\end{definition} +\begin{proof} + $(1) \Rightarrow (2)$: Let $U \subset Y$ be open, then $\pi^{-1}(U)$ is open, so $f \in C(X; Y)$. If $V \subset X$ is saturated and open, then $\pi(V) = \pi(\pi^{-1}(\pi(V)))$ is open. + + $(2) \Rightarrow (1)$: Let $U \subset Y$ be open, then $\pi^{-1}(U)$ is open by continuity. If $V \subset Y$ and $\pi^{-1}(V)$ is open, then $V = \pi(\pi^{-1}(V))$ is open. +\end{proof} + +\begin{definition}[Quotient Space] +\label{definition:quotient-topology} + Let $X$ be a topological space, $\sim$ be an equivalence relation on $X$, then there exists $(\td X, \pi)$ such that: + \begin{enumerate} + \item $\td X$ is a topological space with ground set $X/\sim$. + \item $\pi$ is constant on each equivalence class of $\sim$. + \item $\pi \in C(X; \td X)$. + \item[(U)] For any pair $(Y, f)$ satisfying (1), (2), and (3), there exists a unique $\td f \in C(\td X; Y)$ such that the following diagram commutes: + \[ + \xymatrix{ + X \ar@{->}[d]_{\pi} \ar@{->}[rd]^{f} & \\ + \td X \ar@{->}[r]_{\tilde f} & Y + } + \] + \item $\pi$ is a quotient map. + \end{enumerate} + The space $(\td X, \pi)$ is the \textbf{quotient} of $X$ by $\sim$. +\end{definition} +\begin{proof} + Let $\td X = X/\sim$. For each $U \subset \td X$, define $U$ to be open if and only if $\pi^{-1}(U) \subset X$ is open, then $(\td X, \pi)$ satisfies (1), (2), (3), and (5). + + (U): Since $f$ is constant on each equivalence class of $\sim$, there exists $\td f: \td X \to Y$ such that the diagram commutes. For any $U \subset Y$ open, $\td f^{-1}(U) = \pi(f^{-1}(U))$ is saturated with respect to $\pi$, so $\td f^{-1}(U)$ is open. +\end{proof}