diff --git a/src/fa/lc/tensor.tex b/src/fa/lc/tensor.tex
index 6d6982c..e635017 100644
--- a/src/fa/lc/tensor.tex
+++ b/src/fa/lc/tensor.tex
@@ -53,6 +53,32 @@
     In constructing the \hyperref[projective tensor product]{definition:projective-tensor-product}, it may be more natural to obtain its topology as a projective topology using its universal property. However, doing so requires taking a least upper bound across \textit{all continuous linear maps defined on} $E \times F$, a collection too big to be a set. As such, constructing it as a projective topology is logically dubious, or at the very least beyond my abilities. 
 \end{remark}
 
+\begin{proposition}
+\label{proposition:projective-tensor-product-dual}
+    Let $E, F$ be locally convex space over $K \in \RC$, then
+    \[
+    (E \wh \otimes_\pi F)^* = (E \otimes_\pi F)^* \iso L^2(E, F; K) \iso L(E; F^*) \iso L(F; E^*)
+    \]
+
+    where:
+    \begin{enumerate}
+        \item The dual pairing between $E \otimes_\pi F$ and $L^2(E, F; K)$ is given by
+        \[
+        \angles{\sum_{k = 1}^n x_k \otimes y_k, \lambda}_{E \otimes_\pi F} = \sum_{k = 1}^n \lambda(x_k, y_k)
+        \]
+        \item The dual pairing between $E \otimes_\pi F$ and $L(E; F^*)$ is given by
+        \[
+        \angles{\sum_{k = 1}^n x_k \otimes y_k, T}_{E \otimes_\pi F} = \sum_{k = 1}^n \dpn{y_k, Tx_k}{F}
+        \]
+        \item The dual pairing between $E \otimes_\pi F$ and $L(F; E^*)$ is given by
+        \[
+        \angles{\sum_{k = 1}^n x_k \otimes y_k, T}_{E \otimes_\pi F} = \sum_{k = 1}^n \dpn{x_k, Ty_k}{E}
+        \]
+    \end{enumerate}
+    
+\end{proposition}
+
+
 
 
 \begin{definition}[Cross Seminorm]