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Removed pretentiousness.

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Bokuan Li
2026-06-14 21:29:15 -04:00
parent 16baef24e7
commit 1ec807a9ca
1 changed files with 1 additions and 1 deletions
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src/measure/vector/rn.tex
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@@ -37,7 +37,7 @@
then then
\begin{enumerate} \begin{enumerate}
\item By definition, $\nu = \nu_a + \nu_s$. \item Since $X = A \sqcup B$, $\nu = \nu_a + \nu_s$.
\item Let $E \in \cm$ with $\mu(E) = 0$, then $(1 - g)|_E = 0$ $\lambda$-almost everywhere. Thus $E \subset B$ modulo a $\lambda$-null set, and \item Let $E \in \cm$ with $\mu(E) = 0$, then $(1 - g)|_E = 0$ $\lambda$-almost everywhere. Thus $E \subset B$ modulo a $\lambda$-null set, and
\[ \[
\nu_a(E) = \nu(E \cap A) \le \lambda(A \cap B) = 0 \nu_a(E) = \nu(E \cap A) \le \lambda(A \cap B) = 0