Housekeeping after class.

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Bokuan Li
2026-09-16 13:25:08 -04:00
parent 3a81f8833a
commit 1e76f55d68
3 changed files with 78 additions and 1 deletions
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\begin{definition}[Topological Dynamical System]
\label{definition:topological-dynamical-system}
Let $G$ be a group and $X$ be a compact Hausdorff space, then a \textbf{$G$-flow/topological dynamical system} is a homomorphism $\alpha: G \to \text{Aut}(X)$. In which case, the system is denoted by $G \curvearrowright X$.
Let $G$ be a group and $X$ be a (non-empty) compact Hausdorff space, then a \textbf{$G$-flow/topological dynamical system} is a homomorphism $\alpha: G \to \text{Aut}(X)$. In which case, the system is denoted by $G \curvearrowright X$.
\end{definition}
\begin{definition}[Invariant]
@@ -53,12 +53,48 @@
Let $G \curvearrowright X$ be a $G$-flow and $x \in X$, then $x$ is \textbf{periodic} with respect to $G$ if $Gx$ is finite.
\end{definition}
\begin{definition}[Return Set]
\label{definition:tds-return-set}
Let $G \curvearrowright X$ be a $G$-flow, $x \in X$, and $\emptyset \ne U \subset X$, then the \textbf{return set} of $x$ to $U$ is
\[
N(x, U) = \bracsn{g \in G|gx \in U}
\]
\end{definition}
\begin{definition}[Recurrence]
\label{definition:tds-recurrence}
Let $G$ be an infinite group, $G \curvearrowright X$ be a $G$-flow, and $x \in X$, then $x$ is \textbf{recurrent} if for every $U \in \cn_X(x)$, $N(x, U)$ is infinite.
\end{definition}
\begin{definition}[Syndetic]
\label{definition:group-syndetic}
Let $G$ be a group and $S \subset G$, then $S$ is \textbf{(left) syndetic} if there exists $F \subset G$ finite $FS = G$.
\end{definition}
\begin{lemma}
\label{lemma:subgroup-syndetic}
Let $G$ be a group and $H \subset G$ be a subgroup, then $H$ is syndetic if and only if the index of $H$ in $G$ is finite.
\end{lemma}
% Proof omitted.
\begin{example}
\label{example:z-syndetic}
Let $S \subset \integer$, then $S$ has \textbf{bounded gaps} if
\[
\sup_{n \in \integer}d(n, S) < \infty
\]
The set $S$ has bounded gaps if and only if it is syndetic.
\end{example}
% Proof omitted.
\begin{definition}[Minimality]
\label{definition:tds-minimal}
Let $G \curvearrowright X$ be a $G$-flow, then the following are equivalent:
\begin{enumerate}
\item $G \curvearrowright X$ admits no proper subflows.
\item Every point in $X$ is topologically transitive.
\item For every $x \in X$ and $\emptyset \ne U \subset X$ open, $N(x, U)$ is syndetic in $G$.
\end{enumerate}
@@ -68,6 +104,34 @@
(1) $\Rightarrow$ (2): Let $x \in X$, then $\ol{Gx}$ with the restricted action is a $G$-subflow of $X$. As $\emptyset \ne \ol{Gx}$ and $G \curvearrowright X$ admits no proper subflows, $\ol{Gx} = x$.
(2) $\Rightarrow$ (1): Let $G \curvearrowright Y$ be a $G$-subflow of $G \curvearrowright X$. For any $x \in Y$, $Y \supset \ol{Gx} = X$, so $Y = X$.
(2) $\Rightarrow$ (3): Let $\emptyset \ne U \subset X$ be open. Since $G \curvearrowright X$ is minimal, $Gx \cap U \ne \emptyset$ for all $x \in X$. Thus $X \subset G^{-1}U = GU$. By compactness of $X$, there exists $F \subset G$ finite such that $FU = X$.
Let $x \in X$ be arbitrary, then for each $g \in G$, $gx \in X = FU$. Thus there exists $h \in F$ with $gx \in hU$ and $h^{-1}gx \in U$. Hence $h^{-1}g \in N(x, U)$, and $g \in hN(x, U) \subset FN(x, U)$.
\end{proof}
\begin{lemma}
\label{lemma:tds-minimal-recurrent}
Let $G$ be an infinite group and $G \curvearrowright X$ be minimal $G$-flow, then every point in $X$ is recurrent.
\end{lemma}
\begin{proof}
Let $x \in X$ and $U \in \cn_X(x)$, then $N(x, U)$ is syndetic. As $G$ is infinite, so is $N(x, U)$.
\end{proof}
\begin{theorem}[Existence of Minimal Subflows]
\label{theorem:tds-minimal-existence}
Let $G \curvearrowright X$ be a $G$-flow, then there exists $Y \subset X$ closed such that $G \curvearrowright Y$ is minimal.
\end{theorem}
% Proof omitted.
\begin{corollary}
\label{corollary:tds-recurrent-existence}
Let $G$ be an infinite group and $G \curvearrowright X$ be a $G$-flow, then $X$ admits a recurrent point.
\end{corollary}
\begin{proof}
By \autoref{theorem:tds-minimal-existence}, there exists $Y \subset X$ closed such that $G \curvearrowright X$ is minimal. In which case, \autoref{lemma:tds-minimal-recurrent} implies that every point in $Y$ is recurrent.
\end{proof}