diff --git a/src/fa/interpolation/complex.tex b/src/fa/interpolation/complex.tex new file mode 100644 index 0000000..c7d9d5b --- /dev/null +++ b/src/fa/interpolation/complex.tex @@ -0,0 +1,3 @@ +\section{The Complex Interpolation Method} +\label{section:complex-interpolation} + diff --git a/src/fa/interpolation/functors.tex b/src/fa/interpolation/functors.tex index cc2c835..ad1937c 100644 --- a/src/fa/interpolation/functors.tex +++ b/src/fa/interpolation/functors.tex @@ -5,7 +5,7 @@ \begin{definition}[Compatible Couple] \label{definition:compactible-couple} - Let $E_0, E_1, \mathcal{U}$ be topological vector spaces over $K \in \RC$ and $\iota_0 \in L(E_0; \mathcal{U})$ and $\iota_1 \in L(E_1; \mathcal{U})$ be continuous injections. Under the identification that $E_0$ and $E_1$ are subspaces of $\mathcal{U}$, the pair $(E_0, E_1)$ forms a \textbf{compatible couple} of topological vector spaces. + Let $E_0, E_1$ be topological vector spaces over $K \in \RC$, $\mathcal{U}$ be a separated topological vector space over $K$, and $\iota_0 \in L(E_0; \mathcal{U})$ and $\iota_1 \in L(E_1; \mathcal{U})$ be continuous injections. Under the identification that $E_0$ and $E_1$ are subspaces of $\mathcal{U}$, the pair $(E_0, E_1)$ forms a \textbf{compatible couple} of topological vector spaces. \end{definition} \begin{remark} @@ -59,14 +59,14 @@ \normn{x - \sum_{n = 1}^Nx_n}_{E_0 + E_1} \le \sum_{n > N}\norm{y_n}_{E_0} + \sum_{n > N}\norm{z_n}_{E_1} \le 2\sum_{n > N}\norm{x_n}_{E_0 + E_1} \to 0 \] - as $N \to \infty$. Therefore $E_0 + E_1$ is also a Banach space. + as $N \to \infty$. By \autoref{lemma:banach-criterion}, $E_0 + E_1$ is also a Banach space. \end{proof} \begin{definition}[Category of Compatible Couples] \label{definition:compatible-category} Let $\catc$ be a subcategory of normed spaces over $K \in \RC$ and $(E_0, E_1)$ be a compatible couple, then $E_0 E_1$ are a \textbf{compatible couple in $\catc$} if $E_0, E_1, E_0 \cap E_1, E_0 + E_1 \in \catc$. - Let $(E_0, E_1)$ and $(F_0, F_1)$ be compatible couples in $\catc$ and $T \in L(E_0 + E_1, F_0 + F_1)$, then $T$ is a \textbf{morphism of compatible couples} if $T|_{E_0} \in \text{Mor}_{\catc}(E_0; F_0)$ and $T|_{E_1} \in \text{Mor}(E_1; F_1)$. + Let $(E_0, E_1)$ and $(F_0, F_1)$ be compatible couples in $\catc$ and $T \in L(E_0 + E_1, F_0 + F_1)$, then $T$ is a \textbf{morphism of compatible couples} if $T|_{E_0} \in \text{Mor}_{\catc}(E_0; F_0)$ and $T|_{E_1} \in \text{Mor}_{\catc}(E_1; F_1)$. The collection $\catc_1$ of all compatible couples in $\catc$ equipped with the above definition of morphisms is the \textbf{category of compatible couples} in $\catc$. \end{definition} @@ -111,12 +111,6 @@ \end{definition} - - - - - - \textit{"This is how things appeared in 1965. Fifteen years later, it was found that the number of interpolation methods at our disposal is not large."} — \cite[Page vi, Footnote 3]{brudnyi1991interpolation}. diff --git a/src/fa/norm/normed.tex b/src/fa/norm/normed.tex index ce258d2..a3a5c1e 100644 --- a/src/fa/norm/normed.tex +++ b/src/fa/norm/normed.tex @@ -10,8 +10,44 @@ \item[(SN2)] For any $x \in E$ and $\lambda \in K$, $\norm{\lambda x}_E = \abs{\lambda} \norm{x}_E$. \item[(SN3)] For any $x, y \in E$, $\norm{x + y}_E \le \norm{x}_E + \norm{y}_E$. \end{enumerate} + + In which case, the pair $(E, \norm{\cdot}_E)$ is a \textbf{normed vector space} over $K$. \end{definition} +\begin{definition}[Banach Space] +\label{definition:banach-space} + Let $E$ be a normed vector space over $K \in \RC$, then $E$ is a \textbf{Banach space} if it is complete. +\end{definition} + +\begin{lemma} +\label{lemma:banach-criterion} + Let $E$ be a normed vector space, then the following are equivalent: + \begin{enumerate} + \item $E$ is a Banach space. + \item For each $\seq{x_n} \subset E$ with $\sum_{n \in \natp}\norm{x_n}_E < \infty$, there exists $x \in E$ such that $x = \sum_{n = 1}^\infty x_n$. + \end{enumerate} +\end{lemma} +\begin{proof} + (2) $\Rightarrow$ (1): Let $\seq{x_n} \subset E$ be a Cauchy sequence, then there exists a subsequence $\seq{n_k}$ such that $\norm{x_{n_{k+1}} - x_{n_{k}}}_E < 2^{-k}$ for all $k \in \natp$. For each $k \in \natp$, let $y_k = x_{n_{k+1}} - x_{n_{k}}$, then there exists $y \in E$ such that $y = \sum_{k = 1}^\infty y_k$. Let $\eps > 0$, then there exists $K \in \natp$ such that: + \begin{enumerate}[label=(\alph*)] + \item $\norm{y - \sum_{k = 1}^{K-1} y_k}_E < \eps$. + \item For each $n \ge n_K$, $\norm{x_n - x_{n_K}}_E < \eps$. + \end{enumerate} + + In which case, for every $n \ge n_K$, + \begin{align*} + \norm{x_n - (y + x_{n_1})}_E &< \norm{x_{n_K} - (y + x_{n_1})}_E + \eps \\ + &= \norm{y - \sum_{k = 1}^{K-1} (x_{n_{k+1}} - x_{n_{k}})}_E + \eps \\ + &= \norm{y - \sum_{k = 1}^{K-1} y_k}_E + \epsilon < 2\eps + \end{align*} + + Therefore $x_n \to y + x_{n_1}$ as $n \to \infty$. + + +\end{proof} + + + \begin{proposition} \label{proposition:norm-criterion} Let $E$ be a separated TVS over $K \in \RC$, then the following are equivalent: