Added elementary properties of adjoint maps.
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Bokuan Li
2026-08-08 19:39:18 -04:00
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\section{Adjoint Maps}
\label{section:adjoint-maps}
\begin{definition}[Adjoint Map]
\label{definition:adjoint-map}
Let $E, F$ be vector spaces over a field $K$, and $T \in \hom(E; F)$ be a linear map, then the mapping
\[
T^*: F^* \to E^* \quad \dpn{x, T^*\phi}{E} = \dpn{Tx, \phi}{F}
\]
is the \textbf{algebraic adjoint} of $T$.
\end{definition}
\begin{proposition}
\label{proposition:adjoint-weak-continuous}
Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$ and $T \in \hom(E; G)$, then the following are equivalent:
\begin{enumerate}
\item $T$ is $\sigma(E, F)$-$\sigma(G, H)$ continuous.
\item $T^*(H) \subset F$.
\end{enumerate}
If the above holds, then
\begin{enumerate}[start=2]
\item $T^*|_{H}$ is $\sigma(H, G)$-$\sigma(F, E)$ continuous.
\item $T^{**} = T$.
\end{enumerate}
and the restriction of $T^*$ to $H$ is the \textbf{adjoint} of $T$ with respect to $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$.
\end{proposition}
% Proof omitted due to obviousness.
\begin{proposition}
\label{proposition:adjoint-polar-gymnastics}
Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$, $T: E \to G$ be a $\sigma(E, F)$-$\sigma(G, H)$ continuous linear map, $A \subset E$, and $B \subset G$, then:
\begin{enumerate}
\item $T(A)^\circ = (T^{*})^{-1}(A^\circ)$.
\item If $T(A) \subset B$, then $T^{*}(B^\circ) \subset A^\circ$.
\end{enumerate}
\end{proposition}
\begin{proof}
(1):
\begin{align*}
T(A)^\circ &= \bracsn{\phi \in H| \text{Re}\dpn{Tx, \phi}{\mu} \le 1 \forall x \in A} \\
&= \bracsn{\phi \in H| \text{Re}\dpn{x, T^*\phi}{\lambda} \le 1 \forall x \in A} = (T^{*})^{-1}(A^\circ)
\end{align*}
(2):
\begin{align*}
T^*(B^\circ) &= T^*(\bracs{\phi \in H| \text{Re}\dpn{y, \phi}{\mu} \le 1 \forall y \in B}) \\
&\subset T^*(\bracs{\phi \in H| \text{Re}\dpn{y, \phi}{\mu} \le 1 \forall y \in T(A)}) \\
&= T^*(\bracs{\phi \in H| \text{Re}\dpn{Tx, \phi}{\mu} \le 1 \forall x \in A})\\
&= T^*(\bracs{\phi \in H| \text{Re}\dpn{x, T^*\phi}{\lambda} \le 1 \forall x \in A}) \subset A^\circ
\end{align*}
\end{proof}
\begin{corollary}
\label{corollary:adjoint-kernel-gymnastics}
Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$ and $T: E \to G$ be a $\sigma(E, F)$-$\sigma(G, H)$ continuous linear map, then:
\begin{enumerate}
\item $\ker(T^*) = T(E)^\perp = \bracs{\phi \in H| \dpn{y, \phi}{\mu} = 0 \forall y \in T(E)}$.
\item $T^*$ is injective if and only if $T(E)$ is $\sigma(G, H)$-dense in $G$.
\end{enumerate}
\end{corollary}
\begin{proposition}
\label{proposition:adjoint-continuity}
Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$, $T: E \to G$ be a $\sigma(E, F)$-$\sigma(G, H)$ continuous linear map, $\sigma \subset 2^E$ be a saturated ideal of $\sigma(E, F)$-bounded sets, $\tau \subset 2^G$ be a saturated ideal of $\sigma(G, H)$-bounded sets, then the following are equivalent:
\begin{enumerate}
\item $T^*$ is continuous with respect to the $\tau$-uniform topology on $H$ and the $\sigma$-uniform topology on $F$.
\item $T(\sigma) \subset \tau$.
\end{enumerate}
\end{proposition}
\begin{proof}
(1) $\Rightarrow$ (2): Let $A \in \sigma$, then there exists $B \in \tau$ such that $T^*\phi(A) \subset \ol{B_K(0, 1)}$ for all $\phi \in H$ with $\phi(B) \subset \ol{B_K(0, 1)}$. In which case, $T^*(B^\circ) \subset A^\circ$. Assume without loss of generality that $A$ and $B$ are convex, circled, and closed. By \autoref{proposition:adjoint-polar-gymnastics} applied to $T^*$ and the \hyperref[Bipolar theorem]{theorem:bipolar}, $T(A) \subset B$. Therefore $T(\sigma) \subset \tau$.
\end{proof}

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\input{./definitions.tex} \input{./definitions.tex}
\input{./polar.tex} \input{./polar.tex}
\input{./mackey.tex} \input{./mackey.tex}
\input{./adjoint.tex}

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@@ -13,7 +13,7 @@ Depending on the topology placed on $H \otimes H$, and the corresponding complet
Let $H$ be a complex Hilbert space, then the dual of $H \wh \otimes_\pi H$ is $B(H)$, and the $\sigma(B(H), H \wh \otimes_\pi H)$-topology is the \textbf{ultraweak}/\textbf{$\sigma$-weak} topology on $B(H)$. Let $H$ be a complex Hilbert space, then the dual of $H \wh \otimes_\pi H$ is $B(H)$, and the $\sigma(B(H), H \wh \otimes_\pi H)$-topology is the \textbf{ultraweak}/\textbf{$\sigma$-weak} topology on $B(H)$.
\end{definition} \end{definition}
\begin{proof} \begin{proof}
By \autoref{proposition:projective-tensor-product-dual}. By \autoref{proposition:projective-tensor-product-dual} and the \hyperref[Riesz Representation Theorem]{theorem:riesz-hilbert}.
\end{proof} \end{proof}
Seeing that $B(H)$ is a dual Banach space, the following fact is immediate: Seeing that $B(H)$ is a dual Banach space, the following fact is immediate: