Added Runge's theorem.
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@@ -45,3 +45,13 @@
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\begin{proof}
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Let $C$ be the union of all connected sets that contain $A$, then $C$ is connected by \autoref{proposition:connected-union}, and is the maximum connected set containing $A$ by definition.
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\end{proof}
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\begin{lemma}
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\label{lemma:union-connected-components}
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Let $X$ be a topological space and $A \subset X$ be both open and closed, then $A$ is a union of connected components of $X$.
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\end{lemma}
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\begin{proof}
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Let $C \subset X$ be a connected component, then $C \cap A$ and $C \setminus A$ are both open. Since $C$ is connected, either $C \cap A = \emptyset$ and $C \subset A^c$, or $C \setminus A = \emptyset$ and $C \subset A$.
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\end{proof}
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