Added Banach-Mazur.
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@@ -31,31 +31,6 @@
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(3): For any $A \subset E$, $A = \bigcup_{n \in \natp}A \cap nS$. By \autoref{proposition:separable-metric-space}, $A \cap nS$ is separable for each $n \in \natp$. Therefore $A$ is also separable.
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\end{proof}
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\begin{proposition}
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\label{proposition:separable-banach-borel-sigma-algebra}
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Let $E$ be a separable normed vector space, then the Borel $\sigma$-algebra on $E$ is generated by the following families of sets:
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\begin{enumerate}
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\item Open sets in $E$ with respect to the strong topology.
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\item $\bracs{B(x, r)|x \in E, r > 0}$.
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\item $\bracsn{\ol{B(x, r)}|x \in E, r > 0}$.
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\item Open sets in $E$ with respect to the weak topology.
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\end{enumerate}
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\end{proposition}
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\begin{proof}
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(1) $\Leftrightarrow$ (2) $\Leftrightarrow$ (3): By \autoref{proposition:separable-metric-borel-sigma-algebra}.
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(4) $\subset$ (1): Every weakly open set is strongly open.
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(2) $\subset$ (4): By \autoref{proposition:seminorm-lsc}, $\norm{\cdot}_E: E \to [0, \infty)$ is Borel measurable with respect to the weak topology. For any $x \in E$, let
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\[
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\phi_x: E \to [0, \infty) \quad y \mapsto \norm{x - y}_E
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\]
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then $\phi_x$ is Borel measurable with respect to the weak topology, so $B(x, r) = \bracs{\phi_x < r}$ is a Borel set with respect to the weak topology.
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\end{proof}
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\begin{lemma}
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\label{lemma:compact-embed}
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Let $E$ be a normed vector space over $K \in \RC$ and $A \subset [0, 1]$ be closed, then $C(A; E)$ embeds isometrically into $C([0, 1]; E)$.
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@@ -82,5 +57,59 @@
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Thus there exists $y \in (x - \delta, x)$ with $\norm{Tf(z) - Tf(x)}_E < \eps$ for all $z \in (y, x) \cap [0, 1]$. Similarly, there exists $y' \in (x, x + \delta)$ with $\norm{Tf(z) - Tf(x)}_E < \eps$ for all $z \in (x, y') \cap [0, 1]$. Therefore $Tf$ is continuous at $x$. Since this holds for all $x \in U$ and $x \in A$, $Tf \in C([0, 1]; E)$.
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\end{proof}
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\begin{theorem}[Banach-Mazur]
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\label{theorem:banach-mazur}
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Let $E$ be a separable normed vector space over $K \in \RC$, then there exists an isometric embedding $\iota \in L(E; C([0, 1]; K))$.
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\end{theorem}
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\begin{proof}
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Let $B$ be the closed unit ball of $E^*$, equipped with the weak* topology. By the \hyperref[Hahn-Banach Theorem]{proposition:hahn-banach-utility}, the linear mapping
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\[
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E \to C(B; K) \quad x(\phi) = \dpn{x, \phi}{E}
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\]
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is an isometric embedding. By \autoref{proposition:separable-dual}, $B$ is a compact metric space. The \hyperref[Alexandroff-Hausdorff Theorem]{theorem:cantor-universality} then provides a continuous surjection $f: 2^{\natp} \to B$. Thus the composition map
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\[
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C(B; K) \to C(2^{\natp}; K) \quad g \mapsto g \circ f
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\]
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is a linear isometric embedding. Let $\mathcal{C} \subset [0, 1]$ be the Cantor set, then $\mathcal{C}$ is homeomorphic to $2^{\natp}$ through \autoref{proposition:cantor-space-embedding}. Hence $C(2^{\natp}; K)$ is isometrically isomorphic to $C(\mathcal{C}; K)$.
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Finally, \autoref{lemma:compact-embed} provides yet another linear isometric embedding $C(\mathcal{C}; K) \to C([0, 1]; K)$. Composing the above maps as follows
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\[
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\xymatrix{
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E \ar@{->}[r] & C(B; K) \ar@{->}[r] & C(2^{\mathbb N^+}; K) \ar@{->}[r] & C(\mathcal{C}; K) \ar@{->}[r] & C([0, 1]; K)
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}
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\]
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yields the desired embedding.
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\end{proof}
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\begin{proposition}
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\label{proposition:separable-banach-borel-sigma-algebra}
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Let $E$ be a separable normed vector space, then the Borel $\sigma$-algebra on $E$ is generated by the following families of sets:
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\begin{enumerate}
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\item Open sets in $E$ with respect to the strong topology.
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\item $\bracs{B(x, r)|x \in E, r > 0}$.
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\item $\bracsn{\ol{B(x, r)}|x \in E, r > 0}$.
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\item Open sets in $E$ with respect to the weak topology.
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\end{enumerate}
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\end{proposition}
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\begin{proof}
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(1) $\Leftrightarrow$ (2) $\Leftrightarrow$ (3): By \autoref{proposition:separable-metric-borel-sigma-algebra}.
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(4) $\subset$ (1): Every weakly open set is strongly open.
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(2) $\subset$ (4): By \autoref{proposition:seminorm-lsc}, $\norm{\cdot}_E: E \to [0, \infty)$ is Borel measurable with respect to the weak topology. For any $x \in E$, let
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\[
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\phi_x: E \to [0, \infty) \quad y \mapsto \norm{x - y}_E
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\]
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then $\phi_x$ is Borel measurable with respect to the weak topology, so $B(x, r) = \bracs{\phi_x < r}$ is a Borel set with respect to the weak topology.
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\end{proof}
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