Added Banach-Mazur.

This commit is contained in:
Bokuan Li
2026-08-06 16:19:07 -04:00
parent 3ba29569ef
commit 07bfef705e
3 changed files with 70 additions and 30 deletions

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@@ -31,31 +31,6 @@
(3): For any $A \subset E$, $A = \bigcup_{n \in \natp}A \cap nS$. By \autoref{proposition:separable-metric-space}, $A \cap nS$ is separable for each $n \in \natp$. Therefore $A$ is also separable.
\end{proof}
\begin{proposition}
\label{proposition:separable-banach-borel-sigma-algebra}
Let $E$ be a separable normed vector space, then the Borel $\sigma$-algebra on $E$ is generated by the following families of sets:
\begin{enumerate}
\item Open sets in $E$ with respect to the strong topology.
\item $\bracs{B(x, r)|x \in E, r > 0}$.
\item $\bracsn{\ol{B(x, r)}|x \in E, r > 0}$.
\item Open sets in $E$ with respect to the weak topology.
\end{enumerate}
\end{proposition}
\begin{proof}
(1) $\Leftrightarrow$ (2) $\Leftrightarrow$ (3): By \autoref{proposition:separable-metric-borel-sigma-algebra}.
(4) $\subset$ (1): Every weakly open set is strongly open.
(2) $\subset$ (4): By \autoref{proposition:seminorm-lsc}, $\norm{\cdot}_E: E \to [0, \infty)$ is Borel measurable with respect to the weak topology. For any $x \in E$, let
\[
\phi_x: E \to [0, \infty) \quad y \mapsto \norm{x - y}_E
\]
then $\phi_x$ is Borel measurable with respect to the weak topology, so $B(x, r) = \bracs{\phi_x < r}$ is a Borel set with respect to the weak topology.
\end{proof}
\begin{lemma}
\label{lemma:compact-embed}
Let $E$ be a normed vector space over $K \in \RC$ and $A \subset [0, 1]$ be closed, then $C(A; E)$ embeds isometrically into $C([0, 1]; E)$.
@@ -82,5 +57,59 @@
Thus there exists $y \in (x - \delta, x)$ with $\norm{Tf(z) - Tf(x)}_E < \eps$ for all $z \in (y, x) \cap [0, 1]$. Similarly, there exists $y' \in (x, x + \delta)$ with $\norm{Tf(z) - Tf(x)}_E < \eps$ for all $z \in (x, y') \cap [0, 1]$. Therefore $Tf$ is continuous at $x$. Since this holds for all $x \in U$ and $x \in A$, $Tf \in C([0, 1]; E)$.
\end{proof}
\begin{theorem}[Banach-Mazur]
\label{theorem:banach-mazur}
Let $E$ be a separable normed vector space over $K \in \RC$, then there exists an isometric embedding $\iota \in L(E; C([0, 1]; K))$.
\end{theorem}
\begin{proof}
Let $B$ be the closed unit ball of $E^*$, equipped with the weak* topology. By the \hyperref[Hahn-Banach Theorem]{proposition:hahn-banach-utility}, the linear mapping
\[
E \to C(B; K) \quad x(\phi) = \dpn{x, \phi}{E}
\]
is an isometric embedding. By \autoref{proposition:separable-dual}, $B$ is a compact metric space. The \hyperref[Alexandroff-Hausdorff Theorem]{theorem:cantor-universality} then provides a continuous surjection $f: 2^{\natp} \to B$. Thus the composition map
\[
C(B; K) \to C(2^{\natp}; K) \quad g \mapsto g \circ f
\]
is a linear isometric embedding. Let $\mathcal{C} \subset [0, 1]$ be the Cantor set, then $\mathcal{C}$ is homeomorphic to $2^{\natp}$ through \autoref{proposition:cantor-space-embedding}. Hence $C(2^{\natp}; K)$ is isometrically isomorphic to $C(\mathcal{C}; K)$.
Finally, \autoref{lemma:compact-embed} provides yet another linear isometric embedding $C(\mathcal{C}; K) \to C([0, 1]; K)$. Composing the above maps as follows
\[
\xymatrix{
E \ar@{->}[r] & C(B; K) \ar@{->}[r] & C(2^{\mathbb N^+}; K) \ar@{->}[r] & C(\mathcal{C}; K) \ar@{->}[r] & C([0, 1]; K)
}
\]
yields the desired embedding.
\end{proof}
\begin{proposition}
\label{proposition:separable-banach-borel-sigma-algebra}
Let $E$ be a separable normed vector space, then the Borel $\sigma$-algebra on $E$ is generated by the following families of sets:
\begin{enumerate}
\item Open sets in $E$ with respect to the strong topology.
\item $\bracs{B(x, r)|x \in E, r > 0}$.
\item $\bracsn{\ol{B(x, r)}|x \in E, r > 0}$.
\item Open sets in $E$ with respect to the weak topology.
\end{enumerate}
\end{proposition}
\begin{proof}
(1) $\Leftrightarrow$ (2) $\Leftrightarrow$ (3): By \autoref{proposition:separable-metric-borel-sigma-algebra}.
(4) $\subset$ (1): Every weakly open set is strongly open.
(2) $\subset$ (4): By \autoref{proposition:seminorm-lsc}, $\norm{\cdot}_E: E \to [0, \infty)$ is Borel measurable with respect to the weak topology. For any $x \in E$, let
\[
\phi_x: E \to [0, \infty) \quad y \mapsto \norm{x - y}_E
\]
then $\phi_x$ is Borel measurable with respect to the weak topology, so $B(x, r) = \bracs{\phi_x < r}$ is a Borel set with respect to the weak topology.
\end{proof}